Iklan

Iklan

Pertanyaan

Garis e : x − 3 y + 3 = 0 ditransformasikan terhadap matriks ( 2 1 ​ − 3 2 ​ ) . Hasil transformasi garis e mempunyai persamaan . . . .

Garis ditransformasikan terhadap matriks . Hasil transformasi garis e mempunyai persamaan . . . .

  1. begin mathsize 14px style x space plus space 3 y space minus space 3 space equals space 0 end style

  2. size 14px x size 14px space size 14px minus size 14px space size 14px 3 size 14px y size 14px space size 14px minus size 14px space size 14px 3 size 14px space size 14px equals size 14px space size 14px 0

  3. size 14px x size 14px space size 14px plus size 14px space size 14px 3 size 14px y size 14px space size 14px plus size 14px space size 14px 3 size 14px space size 14px equals size 14px space size 14px 0

  4. size 14px space size 14px 3 size 14px x size 14px space size 14px plus size 14px space size 14px y size 14px space size 14px minus size 14px space size 14px 3 size 14px space size 14px equals size 14px space size 14px 0 

  5. size 14px space size 14px 3 size 14px x size 14px space size 14px minus size 14px space size 14px y size 14px space size 14px plus size 14px space size 14px 3 size 14px space size 14px equals size 14px space size 14px 0

Iklan

M. Alfi

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

hasil transformasi garis mempunyai persamaan A.

hasil transformasi garis begin mathsize 14px style bold italic l end style mempunyai persamaan A. begin mathsize 14px style bold italic x bold plus bold 3 bold italic y bold minus bold 3 bold equals bold 0 end style 

Iklan

Pembahasan

Jadi, hasil transformasi garis mempunyai persamaan A.

begin mathsize 14px style open parentheses table row cell x to the power of apostrophe end cell row cell y to the power of apostrophe end cell end table close parentheses equals open parentheses table row 2 cell negative 3 end cell row cell negative 1 end cell 2 end table close parentheses open parentheses table row x row y end table close parentheses open parentheses table row x row y end table close parentheses equals open parentheses table row 2 cell negative 3 end cell row cell negative 1 end cell 2 end table close parentheses to the power of negative 1 end exponent open parentheses table row cell x to the power of apostrophe end cell row cell y to the power of apostrophe end cell end table close parentheses open parentheses table row x row y end table close parentheses equals open parentheses table row 2 3 row 1 2 end table close parentheses open parentheses table row cell x to the power of apostrophe end cell row cell y to the power of apostrophe end cell end table close parentheses equals open parentheses table row cell 2 x to the power of apostrophe plus 3 y apostrophe end cell row cell x to the power of apostrophe plus 2 y apostrophe end cell end table close parentheses end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell x minus 3 y plus 3 end cell equals 0 row cell 2 x to the power of apostrophe plus 3 y to the power of apostrophe minus 3 left parenthesis x to the power of apostrophe plus 2 y to the power of apostrophe right parenthesis plus 3 end cell equals 0 row cell negative x to the power of apostrophe minus 3 y to the power of apostrophe plus 3 end cell equals 0 row cell x plus 3 y minus 3 end cell equals 0 end table end style

Jadi, hasil transformasi garis begin mathsize 14px style bold italic l end style mempunyai persamaan A. begin mathsize 14px style bold italic x bold plus bold 3 bold italic y bold minus bold 3 bold equals bold 0 end style 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

28

Iklan

Iklan

Pertanyaan serupa

△ O A B dengan koordinat titik O ( 0 , 0 ) , A ( 3 , 0 ) , dan B ( 1 , 6 ) . Jika △ O A B adalah bayangan segitiga O A B oleh transformasi matriks ( 3 1 ​ 4 2 ​ ) , maka luas adalah .... satuan luas.

1

0.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

info@ruangguru.com

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia