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Energi kinetik suatu benda bertambah 300%. Ini berarti momentum benda bertambah sebesar...

Pertanyaan

Energi kinetik suatu benda bertambah 300%. Ini berarti momentum benda bertambah sebesar...space 

  1. 50%space 

  2. 100%space 

  3. 150%space 

  4. 200%space 

  5. 300%space 

Pembahasan Soal:

Soal ini dapat dikerjakan menggunakan hubungan momentum dan energi kinetik.

table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript k end cell equals cell 1 half m v squared end cell row cell E subscript k end cell equals cell fraction numerator open parentheses m v close parentheses squared over denominator 2 m end fraction end cell row cell E subscript k end cell equals cell fraction numerator p squared over denominator 2 m end fraction end cell end table 

Sehingga, Error converting from MathML to accessible text. 

table attributes columnalign right center left columnspacing 0px end attributes row cell E subscript k subscript 1 end subscript over E subscript k subscript 2 end subscript end cell equals cell open parentheses p subscript 1 close parentheses squared over open parentheses p subscript 2 close parentheses squared end cell row cell fraction numerator E subscript k subscript 1 end subscript over denominator open parentheses E subscript k subscript 1 end subscript plus begin display style fraction numerator 300 percent sign over denominator 100 percent sign end fraction end style E subscript k subscript 1 end subscript close parentheses end fraction end cell equals cell open parentheses p subscript 1 close parentheses squared over open parentheses p subscript 2 close parentheses squared end cell row cell fraction numerator E subscript k subscript 1 end subscript over denominator 4 E subscript k subscript 1 end subscript end fraction end cell equals cell p subscript 1 squared over p subscript 2 squared end cell row cell p subscript 2 squared end cell equals cell 4 p subscript 1 squared end cell row cell p subscript 2 end cell equals cell square root of 4 p subscript 1 squared end root end cell row blank equals cell 2 p subscript 1 end cell end table 

Dengan demikian, pertambahan momentumnya

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator increment p over denominator p subscript 1 end fraction cross times 100 percent sign end cell equals cell fraction numerator p subscript 2 minus p subscript 1 over denominator p subscript 1 end fraction cross times 100 percent sign end cell row blank equals cell fraction numerator 2 p subscript 1 minus p subscript 1 over denominator p subscript 1 end fraction cross times 100 percent sign end cell row blank equals cell 100 percent sign end cell end table 

Oleh karena itu, jawaban yang benar adalah B.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Juni 2021

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