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Dua buah bola yang dihubungkan kawat (massa kawat diabaikan) disusun seperti gambar. Besar momen inersia adalah....

Dua buah bola yang dihubungkan kawat (massa kawat diabaikan) disusun seperti gambar.

Besar momen inersia adalah....

  1. 5 comma 5 cross times 10 to the power of negative 2 end exponent k g. m squared

  2. 5 comma 5 cross times 10 to the power of negative 3 end exponent k g. m squared

  3. 1 comma 1 cross times 10 to the power of negative 3 end exponent k g. m squared

  4. 1 comma 1 cross times 10 to the power of negative 2 end exponent k g. m squared

  5. 2 comma 2 cross times 10 to the power of negative 1 end exponent k g. m squared

Jawaban:

R subscript A equals 10 space c m equals 0 comma 1 space m  R subscript B equals 15 space c m equals 0 comma 15 space m  m subscript A equals 200 space g equals 0 comma 2 space k g  m subscript B equals 400 space g equals space 0 comma 4 space k g

 

Coba perhatikan letak sumbu puturnya. Maka:

sum I equals I subscript 1 plus I subscript 2  sum I equals m subscript A R subscript A squared plus m subscript B R subscript B squared  sum I equals left parenthesis 0 comma 2 right parenthesis left parenthesis 0 comma 1 right parenthesis squared plus left parenthesis 0 comma 4 right parenthesis left parenthesis 0 comma 15 right parenthesis squared  sum I equals 0 comma 002 space plus 0 comma 009  sum I equals 0 comma 011 space k g. m squared  sum I equals 1 comma 1 cross times 10 to the power of negative 2 end exponent k g. m squared

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