Roboguru

Dua buah balok  = 1 kg dan  = 2 kg saling terhubun...

Dua buah balok straight m subscript 1 = 1 kg dan straight m subscript 2 = 2 kg saling terhubung oleh tali dengan panjang straight L subscript 2 = 0,5 m. Balok straight m subscript 1 terhubung dengan sumbu licin melalui tali dengan panjang straight L subscript 1 = 1 m seperti terlihat pada gambar. Sistem bergerak melingkar beraturan pada meja mendatar yang licin dengan kecepatan sudut straight omega = 100 rad/s. Jika semua tali ringan dan tidak elastis, besar gaya tegangan pada tali straight L subscript 1 adalah ....

  1. 1 cross times 10 to the power of 4 space straight N

  2. 2 cross times 10 to the power of 4 space straight N

  3. 3 cross times 10 to the power of 4 space straight N

  4. 4 cross times 10 to the power of 4 space straight N

  5. 5 cross times 10 to the power of 4 space straight N

Jawaban:

Rumus space gaya space sentripetal space colon  straight F equals mv squared over straight R equals straight m space straight omega squared space straight R    Tinjau space balok space straight m subscript 2 space colon  straight F subscript straight s 2 end subscript space equals space straight T subscript 2  straight m subscript 2 space. space straight omega subscript 2 squared space. thin space straight R subscript 2 equals straight T subscript 2  left parenthesis 2 right parenthesis space left parenthesis 100 right parenthesis squared space left parenthesis 1 plus 0 comma 5 right parenthesis equals straight T subscript 2  straight T subscript 2 equals 3 cross times 10 to the power of 4 space straight N    Tinjau space balok space straight m subscript 1 space colon  straight F subscript straight s 1 end subscript space plus space straight T subscript 2 equals straight T subscript 1  straight m subscript 1. straight omega subscript 1 squared. straight R subscript 1 plus straight T subscript 2 equals straight T subscript 1  left parenthesis 1 right parenthesis space left parenthesis 100 right parenthesis squared space left parenthesis 1 right parenthesis space plus space left parenthesis 3 space cross times space 10 to the power of 4 right parenthesis equals straight T subscript 1  straight T subscript 1 equals 4 cross times 10 to the power of 4 space straight N

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