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Diketahui tiga buah vektor sebagai berikut. u v w ​ = = = ​ 2 i ⌢ + 2 j ⌢ ​ − k ⌢ 2 i ⌢ − j ⌢ ​ + 3 k ⌢ i ⌢ + j ⌢ ​ − k ⌢ ​ Tentukanlah: a. Vektor satuan dari u ⌢

Diketahui tiga buah vektor sebagai berikut.

Tentukanlah:

a. Vektor satuan dari 

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Diketahui: Vektor . Sehingga diperoleh vektor satuannya adalah: Maka, vektor satuan dari .

Diketahui:

Vektor begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell u with rightwards arrow on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell stack 2 i with overparenthesis on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank plus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 2 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell j with overparenthesis on top end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell k with overparenthesis on top end cell end table end style.

Sehingga diperoleh vektor satuannya adalah:

table attributes columnalign right center left columnspacing 0px end attributes row cell u with rightwards arrow on top end cell equals cell fraction numerator u with rightwards arrow on top over denominator open vertical bar u with rightwards arrow on top close vertical bar end fraction end cell row blank equals cell fraction numerator 1 over denominator square root of 2 squared plus 2 squared plus open parentheses negative 1 close parentheses squared end root end fraction open parentheses 2 comma space 2 comma space minus 1 close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 4 plus 4 plus 1 end root end fraction open parentheses 2 comma space 2 comma space minus 1 close parentheses end cell row blank equals cell fraction numerator 1 over denominator square root of 9 end fraction open parentheses 2 comma space 2 comma space minus 1 close parentheses end cell row blank equals cell 1 third open parentheses 2 comma space 2 comma space minus 1 close parentheses end cell row blank equals cell open parentheses 2 over 3 comma space 2 over 3 comma space minus 1 third close parentheses end cell end table

Maka, vektor satuan dari u with rightwards arrow on top equals open parentheses 2 over 3 i with overparenthesis on top comma 2 over 3 space j with overparenthesis on top comma space minus 1 third k with overparenthesis on top close parentheses.

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