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Pertanyaan

Diketahui a = ⎝ ⎛ ​ − 2 5 − 3 ​ ⎠ ⎞ ​ , b = ⎝ ⎛ ​ 4 − 6 4 ​ ⎠ ⎞ ​ , c = ⎝ ⎛ ​ − 4 11 3 ​ ⎠ ⎞ ​ tentukan 3 a + 2 b !

Diketahui  tentukan !

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I. Kumaralalita

Master Teacher

Mahasiswa/Alumni Universitas Gadjah Mada

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diperoleh .

diperoleh 3 a with rightwards arrow on top plus 2 b with rightwards arrow on top equals open parentheses table row 2 row 3 row cell negative 1 end cell end table close parentheses.

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Pembahasan

Gunakan konsep perkalian vektor dengan skalar, penjumlahan, dan pengurangan vektor. Diketahui , , Perhatikan perhitungan berikut. Jadi, diperoleh .

Gunakan konsep perkalian vektor dengan skalar, penjumlahan, dan pengurangan vektor.

Diketahui a with rightwards arrow on top equals open parentheses table row cell negative 2 end cell row 5 row cell negative 3 end cell end table close parenthesesb with rightwards arrow on top equals open parentheses table row 4 row cell negative 6 end cell row 4 end table close parenthesesc with rightwards arrow on top equals open parentheses table row cell negative 4 end cell row 11 row 3 end table close parentheses

Perhatikan perhitungan berikut.

table attributes columnalign right center left columnspacing 2px end attributes row cell 3 a with rightwards arrow on top plus 2 b with rightwards arrow on top end cell equals cell 3 open parentheses table row cell negative 2 end cell row 5 row cell negative 3 end cell end table close parentheses plus 2 open parentheses table row 4 row cell negative 6 end cell row 4 end table close parentheses end cell row blank equals cell open parentheses table row cell 3 cross times open parentheses negative 2 close parentheses end cell row cell 3 cross times 5 end cell row cell 3 cross times open parentheses negative 3 close parentheses end cell end table close parentheses plus open parentheses table row cell 2 cross times 4 end cell row cell 2 cross times open parentheses negative 6 close parentheses end cell row cell 2 cross times 4 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell negative 6 end cell row 15 row cell negative 9 end cell end table close parentheses plus open parentheses table row 8 row cell negative 12 end cell row 8 end table close parentheses end cell row blank equals cell open parentheses table row cell negative 6 plus 8 end cell row cell 15 minus 12 end cell row cell negative 9 plus 8 end cell end table close parentheses end cell row cell 3 a with rightwards arrow on top plus 2 b with rightwards arrow on top end cell equals cell open parentheses table row 2 row 3 row cell negative 1 end cell end table close parentheses end cell end table

Jadi, diperoleh 3 a with rightwards arrow on top plus 2 b with rightwards arrow on top equals open parentheses table row 2 row 3 row cell negative 1 end cell end table close parentheses.

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Diketahui vektor p ​ = ( 3 4 ​ ) , vektor q ​ = ( 5 − 1 ​ ) , dan vektor r = ( − 2 6 ​ ) . Tentukan: b) p ​ + 2 q ​ − 3 r

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