Roboguru

Diketahui suatu layang-layang berkoordinat di titi...

Diketahui suatu layang-layang berkoordinat di titik begin mathsize 14px style straight K open parentheses negative 5 comma 0 close parentheses comma space straight L open parentheses 0 comma 12 close parentheses comma space straight M open parentheses 16 comma 0 close parentheses comma space dan space straight N open parentheses 0 comma negative 12 close parentheses end style. Keliling layang-layang begin mathsize 14px style KLMN end style adalah ....

  1. 33 satuan

  2. 52 satuan

  3. 66 satuan

  4. 80 satuan

Jawaban:

Ilustrasi dari soal adalah sebagai berikut:



Panjang size 14px a size 14px equals size 14px d, dengan menggunakan Teorema Pythagoras maka didapatkan:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank a end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank d end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 12 squared plus 5 squared end root end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank a end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank d end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 144 plus 25 end root end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank a end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank d end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell square root of 169 end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank a end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank d end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 13 end table end style     

Panjang begin mathsize 14px style b equals c end style, dengan menggunakan Teorema Pythagoras maka didapatkan:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row b equals cell c equals square root of 12 squared plus 16 squared end root end cell row b equals cell c equals square root of 144 plus 256 end root end cell row b equals cell c equals square root of 400 end cell row b equals cell c equals 20 end cell end table end style   

Sehingga, kelilingnya didapatkan:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row K equals cell a plus b plus c plus d end cell row blank equals cell 13 plus 20 plus 20 plus 13 end cell row blank equals 66 end table end style 

Dengan demikian, keliling layang-layang begin mathsize 14px style KLMN end style adalah 66 satuan.

Jadi, jawaban yang benar adalah C.

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved