Roboguru

Diketahui proyeksi skalar ortogonal   pada   adala...

Diketahui proyeksi skalar ortogonal a with rightwards arrow on top equals open parentheses table row 3 row cell negative 4 end cell end table close parentheses  pada b with rightwards arrow on top equals open parentheses table row cell negative 2 end cell row p end table close parentheses  adalahnegative 2 square root of 5 Tentukan:

a. Nilai p

Jawaban:

Untuk menentukan nilai p, kita daoat menggunakan rumus proyeksi skala orthogonal vektor a with rightwards arrow on top pada b with rightwards arrow on top

table attributes columnalign right center left columnspacing 0px end attributes row cell open vertical bar p with rightwards arrow on top close vertical bar end cell equals cell fraction numerator a with rightwards arrow on top b with rightwards arrow on top over denominator b with rightwards arrow on top end fraction end cell row cell negative 2 square root of 5 end cell equals cell fraction numerator 3 open parentheses negative 2 close parentheses plus open parentheses negative 4 close parentheses open parentheses p close parentheses over denominator square root of open parentheses negative 2 close parentheses squared plus p squared end root end fraction end cell row cell negative 2 square root of 5 end cell equals cell fraction numerator negative 6 minus 4 p over denominator square root of 4 plus p squared end root end fraction end cell row cell square root of open parentheses 4 plus p squared close parentheses 5 end root end cell equals cell fraction numerator negative 6 minus 4 p over denominator negative 2 end fraction end cell row cell square root of 20 plus 5 p squared end root end cell equals cell 3 plus 2 p end cell row cell 20 plus 5 p squared end cell equals cell 9 plus 12 p plus 4 p squared end cell row cell 5 p squared minus 4 p squared minus 12 p plus 20 minus 9 end cell equals 0 row cell p squared minus 12 p plus 11 end cell equals 0 row cell open parentheses p minus 1 close parentheses open parentheses p minus 11 close parentheses end cell equals 0 row p equals cell 1 space atau space p equals 11 end cell end table  

Jadi, nilai p adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank p end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 1 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank atau end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank space end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank p end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 11 end table 

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved