Roboguru

Diketahui nomor atom Zn = 30, konfigurasi elektron...

Diketahui nomor atom Zn = 30, konfigurasi elektron ion begin mathsize 14px style Zn to the power of plus 2 end exponent end style adalah ....

  1. begin mathsize 14px style 1 s squared 2 s squared 2 p to the power of 6 3 s squared 3 p to the power of 6 4 s squared 3 d to the power of 10 end style

  2. begin mathsize 14px style 1 s squared 2 s squared 2 p to the power of 6 3 s squared 3 p to the power of 6 4 s to the power of 1 3 d to the power of 9 end style

  3. begin mathsize 14px style 1 s squared 2 s squared 2 p to the power of 6 3 s squared 3 p to the power of 6 4 s squared 3 d to the power of 8 end style

  4. begin mathsize 14px style 1 s squared 2 s squared 2 p to the power of 6 3 s squared 3 p to the power of 6 3 d to the power of 10 end style

  5. begin mathsize 14px style 1 s squared 2 s squared 2 p to the power of 6 3 s squared 3 p to the power of 6 4 s squared 3 d to the power of 9 end style

Jawaban:

Konfigurasi elektron begin mathsize 14px style Zn presubscript 30 equals 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space 4 s squared space 3 d to the power of 10 end style

Ion begin mathsize 14px style Zn to the power of plus 2 end exponent end style artinya atom Zn melepas 2 elektron terluarnya. Elektron terluarnya terdapat pada orbital 4s, maka elektron yang terlepas adalah dari orbital 4s. Sehingga konfigurasi elektron ion undefined adalah:

Konfigurasi elektron begin mathsize 14px style Zn to the power of plus 2 end exponent equals 1 s squared space 2 s squared space 2 p to the power of 6 space 3 s squared space 3 p to the power of 6 space 3 d to the power of 10 end style


Jadi, jawaban yang tepat adalah D.

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