Roboguru

Diketahui: massa = 9 gram massa air (p) = 100 gram Ditanya:

Pertanyaan

Diketahui:

  • massa = 9 gram
  • massa air (p) = 100 gram
  • begin mathsize 14px style T subscript f equals minus sign 0 comma 93 to the power of o C end style
  • begin mathsize 14px style K subscript f equals 1 comma 86 to the power of o C forward slash m end style
  • begin mathsize 14px style K subscript b equals 0 comma 52 to the power of o C forward slash m end style

Ditanya:

  • begin mathsize 14px style M subscript r space senyawa end style
  • begin mathsize 14px style T subscript b end style

Pembahasan Soal:

Menghitung italic M subscript italic r senyawa

table attributes columnalign right center left columnspacing 0px end attributes row cell T subscript f end cell equals cell 0 degree C minus sign increment T subscript f end cell row cell increment T subscript f end cell equals cell 0 degree C bond T subscript f end cell row cell increment T subscript f end cell equals cell 0 degree C minus sign left parenthesis minus sign 0 comma 93 degree C right parenthesis end cell row cell increment T subscript f end cell equals cell 0 comma 93 degree C end cell row blank blank blank row cell increment T subscript f end cell equals cell K subscript f cross times fraction numerator massa space senyawa over denominator M subscript r end fraction cross times fraction numerator 1000 over denominator massa space pelarut end fraction end cell row cell 0 comma 93 degree C end cell equals cell 1 comma 86 degree C space m to the power of negative sign 1 end exponent cross times fraction numerator 9 space gram over denominator M subscript r end fraction cross times fraction numerator 1000 over denominator 100 space gram end fraction end cell row cell M subscript r end cell equals cell fraction numerator 1 comma 86 degree C space m to the power of negative sign 1 end exponent cross times 9 space gram cross times 1000 over denominator 0 comma 93 degree C cross times 100 space gram end fraction end cell row cell M subscript r end cell equals cell 180 space gram space mol to the power of negative sign 1 end exponent end cell end table 

Jadi italic M subscript italic r senyawa adalah bold 180 bold space bold gram bold space bold mol to the power of bold minus sign bold 1 end exponent.
 

Menghitung nilai italic T subscript italic b 

table attributes columnalign right center left columnspacing 0px end attributes row cell increment T subscript b end cell equals cell K subscript b cross times fraction numerator massa space senyawa over denominator M subscript r end fraction cross times fraction numerator 1000 over denominator massa space pelarut end fraction end cell row cell increment T subscript b end cell equals cell 0 comma 52 degree C space m to the power of negative sign 1 end exponent cross times fraction numerator 9 space gram over denominator 180 space gram space mol to the power of negative sign 1 end exponent end fraction cross times fraction numerator 1000 over denominator 100 space gram end fraction end cell row cell increment T subscript b end cell equals cell 0 comma 26 degree C end cell row cell T subscript b end cell equals cell T to the power of degree subscript b plus increment T subscript b end cell row cell T subscript b end cell equals cell 100 degree C plus 0 comma 26 degree C end cell row cell T subscript b end cell equals cell 100 comma 26 degree C end cell end table 

Jadi nilai italic T subscript italic b adalah bold 100 bold comma bold 26 bold degree C.space 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 02 Juni 2021

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