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Diketahui K sp ​ PbCl 2 ​ = 4 × 1 0 − 18 , maka kelarutan PbCl 2 ​ dalam larutan CaCl 2 ​ 0 , 05 M adalah ....

Diketahui , maka kelarutan  dalam larutan  adalah ....

  1. begin mathsize 14px style 1 cross times 10 to the power of negative sign 7 end exponent end style M

  2. begin mathsize 14px style 4 cross times 10 to the power of negative sign 16 end exponent end style M

  3. begin mathsize 14px style 1 comma 6 cross times 10 to the power of negative sign 16 end exponent end style M

  4. begin mathsize 14px style 4 cross times 10 to the power of negative sign 17 end exponent end style M

  5. begin mathsize 14px style 4 cross times 10 to the power of negative sign 19 end exponent end style M

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S. Lubis

Master Teacher

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maka jawaban yang tepat adalah B.

maka jawaban yang tepat adalah B.

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Dengan demikian, maka jawaban yang tepat adalah B.

table attributes columnalign right center left columnspacing 0px end attributes row cell Ca Cl subscript 2 open parentheses italic a italic q close parentheses end cell rightwards arrow cell Ca to the power of 2 plus sign open parentheses italic a italic q close parentheses plus 2 Cl to the power of minus sign open parentheses italic a italic q close parentheses end cell row cell open square brackets Cl to the power of minus sign close square brackets end cell equals cell 2 space open square brackets Ca Cl subscript 2 close square brackets end cell row cell open square brackets Cl to the power of minus sign close square brackets end cell equals cell 2 cross times 0 comma 05 space M end cell row blank equals cell space 0 comma 1 space M end cell row blank blank blank row cell Pb Cl subscript 2 open parentheses italic s close parentheses end cell rightwards harpoon over leftwards harpoon cell Pb to the power of 2 plus sign open parentheses italic a italic q close parentheses plus 2 Cl to the power of minus sign open parentheses italic a italic q close parentheses end cell row cell K subscript sp end cell equals cell open square brackets Pb to the power of 2 plus sign close square brackets open square brackets Cl to the power of minus sign close square brackets squared space end cell row cell 4 cross times 10 to the power of negative sign 18 end exponent end cell equals cell open square brackets Pb to the power of 2 plus sign close square brackets open parentheses 0 comma 1 close parentheses squared end cell row cell open square brackets Pb to the power of 2 plus sign close square brackets end cell equals cell 4 cross times 10 to the power of negative sign 16 end exponent space M end cell end table

Dengan demikian, maka jawaban yang tepat adalah B.

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