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Diketahui Ksp , maka kelarutan dalam larutan 0,05 M adalah ....

Diketahui Ksp begin mathsize 14px style Pb Cl subscript 2 equals 4 middle dot 10 to the power of negative sign 18 end exponent end style, maka kelarutan undefined dalam larutan begin mathsize 14px style Ca Cl subscript 2 end style 0,05 M adalah ....undefined 

  1. begin mathsize 14px style 1 middle dot 10 to the power of negative sign 7 end exponent space M end style

  2. begin mathsize 14px style 4 middle dot 10 to the power of negative sign 16 end exponent space M end style

  3. begin mathsize 14px style 1 comma 6 middle dot 10 to the power of negative sign 16 end exponent space M end style

  4. begin mathsize 14px style 4 middle dot 10 to the power of negative sign 17 end exponent space M end style

  5. begin mathsize 14px style 4 middle dot 10 to the power of negative sign 19 end exponent space M end style

Jawaban:

Pengaruh ion senama akan memperkecil kelarutan senyawa elektrolit.

begin mathsize 14px style Ca Cl subscript 2 space space space space space space end subscript yields space space space Ca to the power of 2 plus sign space space space space plus space space 2 Cl to the power of minus sign space 0 comma 05 space M space space space space space space space space space 0 comma 05 space M space space space space space space 2 cross times 0 comma 05 space M space equals 0 comma 1 space M  Pb Cl subscript 2 space space space space space rightwards harpoon over leftwards harpoon space space space Pb to the power of 2 plus sign space space space plus space space 2 Cl to the power of minus sign space space space space s space space space space space space space space space space space space space space space space space space space space s space space space space space space space space space space space space 2 s end style 

begin mathsize 14px style Ksp equals open square brackets Pb to the power of 2 plus sign close square brackets open square brackets Cl to the power of minus sign close square brackets squared 4 middle dot 10 to the power of negative sign 18 end exponent equals open square brackets s close square brackets open square brackets 0 comma 1 close square brackets squared space 4 middle dot 10 to the power of negative sign 18 end exponent equals 0 comma 01 s s equals fraction numerator 4 middle dot 10 to the power of negative sign 18 end exponent over denominator 0 comma 01 end fraction s equals 4 middle dot 10 to the power of negative sign 16 end exponent end style 

Berdasarkan penjelasan diatas, kelarutan undefined dalam begin mathsize 14px style Ca Cl subscript 2 space 0 comma 05 space M end style adalah begin mathsize 14px style 4 middle dot 10 to the power of negative sign 16 end exponent end style.

Jadi, jawaban yang benar adalah B.undefined 

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