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Diketahui koordinat titik  dan . Jika , koordinat ...

Diketahui koordinat titik straight M left parenthesis 3 comma space 2 comma space minus 4 right parenthesis dan straight N left parenthesis 1 comma space minus 1 comma space 2 right parenthesis. Jika MN with rightwards arrow on top space colon space NP with rightwards arrow on top equals 1 space colon space 2, koordinat titik P adalah ...

  1. left parenthesis 5 over 3 comma space 0 comma space 0 right parenthesis 

  2. left parenthesis 7 over 3 comma space 1 comma space minus 2 right parenthesis 

  3. left parenthesis 7 comma space 8 comma space minus 16 right parenthesis 

  4. left parenthesis 3 comma space 7 comma space minus 14 right parenthesis 

  5. left parenthesis negative 3 comma space minus 7 comma space 14 right parenthesis 

Jawaban:

Diketahui : straight M left parenthesis 3 comma space 2 comma space minus 4 right parenthesis,  straight N left parenthesis 1 comma space minus 1 comma space 2 right parenthesisMN with rightwards arrow on top space colon space NP with rightwards arrow on top equals 1 space colon space 2 

Cari P dari perbandingan yang telah diketahuispace 

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator MN with rightwards arrow on top over denominator NP with rightwards arrow on top end fraction end cell equals cell 1 half end cell row cell 2 MN with rightwards arrow on top end cell equals cell NP with rightwards arrow on top end cell row cell 2 left parenthesis straight N minus straight M right parenthesis end cell equals cell straight P minus straight N end cell row cell 2 straight N minus 2 straight M end cell equals cell straight P minus straight N end cell row cell 2 straight N plus straight N minus 2 straight M end cell equals straight P row cell 3 straight N minus 2 straight M end cell equals straight P row straight P equals cell 3 straight N minus 2 straight M end cell end table

Selanjutnya substitusikan titik M dan Nspace 

table attributes columnalign right center left columnspacing 0px end attributes row straight P equals cell 3 straight N minus 2 straight M end cell row blank equals cell 3 open parentheses table row 1 row cell negative 1 end cell row 2 end table close parentheses minus 2 open parentheses table row 3 row 2 row cell negative 4 end cell end table close parentheses end cell row blank equals cell open parentheses table row 3 row cell negative 3 end cell row 6 end table close parentheses minus open parentheses table row 6 row 4 row cell negative 8 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell negative 3 end cell row cell negative 7 end cell row 14 end table close parentheses end cell end table   

Oleh karena itu, jawaban yang benar adalah E.space 

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