Roboguru

Diketahui koordinat titik , , dan . Hasil perkalian  adalah ....

Pertanyaan

Diketahui koordinat titik straight P open parentheses 3 comma space minus 1 comma space 4 close parenthesesstraight Q open parentheses negative 2 comma space 1 comma space minus 5 close parentheses, dan straight R open parentheses 4 comma space 3 comma space minus 2 close parentheses. Hasil perkalian PQ with rightwards arrow on top times PR with rightwards arrow on top adalah ....

  1. 67 

  2. 41 

  3. negative 51 

  4. negative 57 

  5. negative 67 

Pembahasan Soal:

Gunakan konsep dot produk pada vektor.

Diketahui koordinat titik straight P open parentheses 3 comma space minus 1 comma space 4 close parenthesesstraight Q open parentheses negative 2 comma space 1 comma space minus 5 close parentheses, dan straight R open parentheses 4 comma space 3 comma space minus 2 close parentheses. Akan ditentukan hasil perkalian PQ with rightwards arrow on top times PR with rightwards arrow on top.

*Menentukan PQ with rightwards arrow on top.

table attributes columnalign right center left columnspacing 2px end attributes row cell PQ with rightwards arrow on top end cell equals cell straight Q minus straight P end cell row blank equals cell open parentheses table row cell negative 2 end cell row 1 row cell negative 5 end cell end table close parentheses minus open parentheses table row 3 row cell negative 1 end cell row 4 end table close parentheses end cell row blank equals cell open parentheses table row cell negative 2 minus 3 end cell row cell 1 minus open parentheses negative 1 close parentheses end cell row cell negative 5 minus 4 end cell end table close parentheses end cell row cell PQ with rightwards arrow on top end cell equals cell open parentheses table row cell negative 5 end cell row 2 row cell negative 9 end cell end table close parentheses end cell end table

*Menentukan PR with rightwards arrow on top.

table attributes columnalign right center left columnspacing 2px end attributes row cell PR with rightwards arrow on top end cell equals cell straight R minus straight P end cell row blank equals cell open parentheses table row 4 row 3 row cell negative 2 end cell end table close parentheses minus open parentheses table row 3 row cell negative 1 end cell row 4 end table close parentheses end cell row blank equals cell open parentheses table row cell 4 minus 3 end cell row cell 3 minus open parentheses negative 1 close parentheses end cell row cell negative 2 minus 4 end cell end table close parentheses end cell row cell PR with rightwards arrow on top end cell equals cell open parentheses table row 1 row 4 row cell negative 6 end cell end table close parentheses end cell end table

Sehingga nilai PQ with rightwards arrow on top times PR with rightwards arrow on top dapat dihitung sebagai berikut.

table attributes columnalign right center left columnspacing 2px end attributes row cell PQ with rightwards arrow on top times PR with rightwards arrow on top end cell equals cell open parentheses table row cell negative 5 end cell row 2 row cell negative 9 end cell end table close parentheses times open parentheses table row 1 row 4 row cell negative 6 end cell end table close parentheses end cell row blank equals cell open parentheses negative 5 close parentheses open parentheses 1 close parentheses plus open parentheses 2 close parentheses open parentheses 4 close parentheses plus open parentheses negative 9 close parentheses open parentheses negative 6 close parentheses end cell row blank equals cell negative 5 plus 8 plus 54 end cell row cell PQ with rightwards arrow on top times PR with rightwards arrow on top end cell equals 57 end table

Diperoleh hasil perkalian PQ with rightwards arrow on top times PR with rightwards arrow on top adalah 57.

Jadi, tidak ada jawaban yang tepat.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 04 Juni 2021

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