Roboguru

Diketahui fungsi . Jika daerah asal  adalah . Jika , grafik fungsi  adalah ....

Pertanyaan

Diketahui fungsi begin mathsize 14px style f colon x rightwards arrow 1 minus 1 half x end style. Jika daerah asal begin mathsize 14px style f end style adalah begin mathsize 14px style D subscript f equals left curly bracket x left enclose x less than 6 comma x element of straight R end enclose right curly bracket end style. Jika begin mathsize 14px style g left parenthesis x right parenthesis equals open vertical bar f left parenthesis x right parenthesis close vertical bar end style, grafik fungsi begin mathsize 14px style y equals g left parenthesis x right parenthesis end style adalah ....

  1.  

     

  2.    

     

     

  3.  

     

  4.  

Pembahasan Soal:

Diketahui: 

fungsi begin mathsize 14px style f colon x rightwards arrow 1 minus 1 half x end style dengan daerah asal begin mathsize 14px style f end style adalah begin mathsize 14px style D subscript f equals left curly bracket x left enclose x less than 6 comma x element of straight R end enclose right curly bracket end style

 begin mathsize 14px style g left parenthesis x right parenthesis equals open vertical bar f left parenthesis x right parenthesis close vertical bar end style

Ditanya:

grafik fungsi begin mathsize 14px style y equals g left parenthesis x right parenthesis end style?

Jawab:

begin mathsize 14px style y equals g left parenthesis x right parenthesis equals open vertical bar f left parenthesis x right parenthesis close vertical bar equals open vertical bar 1 minus 1 half x close vertical bar g left parenthesis negative 2 right parenthesis equals open vertical bar 1 minus 1 half times open parentheses negative 2 close parentheses close vertical bar equals open vertical bar 1 plus 1 close vertical bar equals 2 g left parenthesis negative 1 right parenthesis equals open vertical bar 1 minus 1 half times left parenthesis negative 1 right parenthesis close vertical bar equals open vertical bar 1 plus 1 half close vertical bar equals 3 over 2 g left parenthesis 0 right parenthesis equals open vertical bar 1 minus 1 half times open parentheses 0 close parentheses close vertical bar equals open vertical bar 1 minus 0 close vertical bar equals 1 g left parenthesis 1 right parenthesis equals open vertical bar 1 minus 1 half times open parentheses 1 close parentheses close vertical bar equals open vertical bar 1 minus 1 half close vertical bar equals 1 half g left parenthesis 2 right parenthesis equals open vertical bar 1 minus 1 half times open parentheses 2 close parentheses close vertical bar equals open vertical bar 1 minus 1 close vertical bar equals 0 g left parenthesis 6 right parenthesis equals open vertical bar 1 minus 1 half times open parentheses 6 close parentheses close vertical bar equals open vertical bar 1 minus 3 close vertical bar equals 2 end style 

Jadi, jawaban yang tepat adalah C.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 14 Maret 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved