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Diketahui ( g ∘ f ) ( x ) = 4 x 3 + 4 x dan g ( x ) = x 2 − 1 . Tentukanlah nilai f ( x − 2 ) .

Diketahui  dan . Tentukanlah nilai .

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I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

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atau .

 begin mathsize 14px style f left parenthesis x minus 2 right parenthesis equals square root of 4 left parenthesis x minus 2 right parenthesis cubed plus 4 left parenthesis x minus 2 right parenthesis plus 1 end root end style atau begin mathsize 14px style f left parenthesis x minus 2 right parenthesis equals negative square root of 4 left parenthesis x minus 2 right parenthesis cubed plus 4 left parenthesis x minus 2 right parenthesis plus 1 end root end style.

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atau Jadi, atau .

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell left parenthesis g ring operator f right parenthesis left parenthesis x right parenthesis end cell equals cell 4 x cubed plus 4 x end cell row cell g left parenthesis f left parenthesis x right parenthesis right parenthesis end cell equals cell 4 x cubed plus 4 x end cell row cell open parentheses f left parenthesis x right parenthesis close parentheses squared minus 1 end cell equals cell 4 x cubed plus 4 x end cell row cell open parentheses f left parenthesis x right parenthesis close parentheses squared end cell equals cell 4 x cubed plus 4 x plus 1 end cell end table end style

begin mathsize 14px style f left parenthesis x right parenthesis equals square root of 4 x cubed plus 4 x plus 1 end root end style atau begin mathsize 14px style f left parenthesis x right parenthesis equals negative square root of 4 x cubed plus 4 x plus 1 end root end style

Jadi, begin mathsize 14px style f left parenthesis x minus 2 right parenthesis equals square root of 4 left parenthesis x minus 2 right parenthesis cubed plus 4 left parenthesis x minus 2 right parenthesis plus 1 end root end style atau begin mathsize 14px style f left parenthesis x minus 2 right parenthesis equals negative square root of 4 left parenthesis x minus 2 right parenthesis cubed plus 4 left parenthesis x minus 2 right parenthesis plus 1 end root end style.

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