Iklan

Iklan

Pertanyaan

Diketahui A = [ 2 − 3 ​ − 1 3 ​ ] , C = [ 1 2 ​ 2 5 ​ ] , dan D = [ 3 6 ​ 0 9 ​ ] . Jika A ⋅ B ⋅ C = D maka matriks B adalah...

Diketahui  dan  Jika  maka matriks B adalah...space 

Iklan

R. Diah

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Jawaban

nilai matriks B adalah .

nilai matriks B adalah open square brackets table row 19 cell negative 7 end cell row 23 cell negative 8 end cell end table close square brackets .space      space 

Iklan

Pembahasan

Perhatikan penghitungan berikut! Jadi, nilai matriks B adalah .

Perhatikan penghitungan berikut!

 straight A times straight B times straight C equals straight D straight A to the power of negative 1 end exponent times straight A times straight B times straight C equals straight A to the power of negative 1 end exponent times straight D straight I times straight B times straight C equals straight A to the power of negative 1 end exponent times straight D straight B times straight C equals straight A to the power of negative 1 end exponent times straight D straight B times straight C times straight C to the power of negative 1 end exponent equals straight A to the power of negative 1 end exponent times straight D times straight C to the power of negative 1 end exponent straight B times straight I equals straight A to the power of negative 1 end exponent times straight D times straight C to the power of negative 1 end exponent straight B equals straight A to the power of negative 1 end exponent times straight D times straight C to the power of negative 1 end exponent straight A equals open square brackets table row 2 cell negative 1 end cell row cell negative 3 end cell 3 end table close square brackets space rightwards arrow straight A to the power of negative 1 end exponent equals fraction numerator 1 over denominator open parentheses 2 cross times 3 close parentheses minus open parentheses negative 1 cross times negative 3 close parentheses end fraction open square brackets table row 3 1 row 3 2 end table close square brackets straight A to the power of negative 1 end exponent equals 1 third open square brackets table row 3 1 row 3 2 end table close square brackets  straight C equals open square brackets table row 1 2 row 2 5 end table close square brackets space rightwards arrow straight C to the power of negative 1 end exponent equals fraction numerator 1 over denominator open parentheses 1 cross times 5 close parentheses minus open parentheses 2 cross times 2 close parentheses end fraction open square brackets table row 5 cell negative 2 end cell row cell negative 2 end cell 1 end table close square brackets straight C to the power of negative 1 end exponent equals 1 over 1 open square brackets table row 5 cell negative 2 end cell row cell negative 2 end cell 1 end table close square brackets equals open square brackets table row 5 cell negative 2 end cell row cell negative 2 end cell 1 end table close square brackets  straight B equals straight A to the power of negative 1 end exponent times straight D times straight C to the power of negative 1 end exponent straight B equals 1 third open square brackets table row 3 1 row 3 2 end table close square brackets times open square brackets table row 3 0 row 6 9 end table close square brackets times open square brackets table row 5 cell negative 2 end cell row cell negative 2 end cell 1 end table close square brackets straight B equals 1 third open square brackets table row 15 9 row 21 18 end table close square brackets times open square brackets table row 5 cell negative 2 end cell row cell negative 2 end cell 1 end table close square brackets straight B equals 1 third open square brackets table row 57 cell negative 21 end cell row 69 cell negative 24 end cell end table close square brackets straight B equals open square brackets table row 19 cell negative 7 end cell row 23 cell negative 8 end cell end table close square brackets                

Jadi, nilai matriks B adalah open square brackets table row 19 cell negative 7 end cell row 23 cell negative 8 end cell end table close square brackets .space      space 

Perdalam pemahamanmu bersama Master Teacher
di sesi Live Teaching, GRATIS!

1

Najla Putri

Pembahasan lengkap banget Ini yang aku cari! Mudah dimengerti Makasih ❤️

Iklan

Iklan

Pertanyaan serupa

Diberikan matriks A = ( 15 6 ​ 3 9 ​ ) , B = ( 2 3 ​ a 10 ​ ) dan C = ( 1 3 ​ − 4 − 13 ​ ) . Jika memenuhi persamaan A = B + C − 1 , maka nilai adalah ...

4

5.0

Jawaban terverifikasi

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Roboguru

Coba GRATIS Aplikasi Ruangguru

Download di Google PlayDownload di AppstoreDownload di App Gallery

Produk Ruangguru

Hubungi Kami

Ruangguru WhatsApp

+62 815-7441-0000

Email info@ruangguru.com

[email protected]

Contact 02140008000

02140008000

Ikuti Kami

©2024 Ruangguru. All Rights Reserved PT. Ruang Raya Indonesia