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Diketahui , , dan . Jika 3 a − b = k c , maka k a = ....

Diketahui begin mathsize 14px style a with rightwards arrow on top equals open parentheses table row 2 row 4 row 1 end table close parentheses end stylebegin mathsize 14px style b with rightwards arrow on top equals open parentheses table row 8 row cell negative 2 end cell row cell negative 5 end cell end table close parentheses end style, dan begin mathsize 14px style c with rightwards arrow on top equals open parentheses table row cell negative 1 end cell row 7 row 4 end table close parentheses end style. Jika , maka ....

  1. begin mathsize 14px style 6 i with rightwards arrow on top plus 12 j with rightwards arrow on top plus 3 k with rightwards arrow on top end style  

  2. begin mathsize 14px style 4 i with rightwards arrow on top plus 8 j with rightwards arrow on top plus 2 k with rightwards arrow on top end style  

  3. begin mathsize 14px style 2 i with rightwards arrow on top plus 4 j with rightwards arrow on top plus 1 k with rightwards arrow on top end style  

  4. begin mathsize 14px style negative 2 i with rightwards arrow on top plus 14 j with rightwards arrow on top plus 8 k with rightwards arrow on top end style  

  5. begin mathsize 14px style negative i with rightwards arrow on top plus 7 j with rightwards arrow on top plus 4 k with rightwards arrow on top end style  

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Pembahasan

Perhatikan bahwa Sehingga .Maka k = 2. Akibatnya didapatkan bahwa

Perhatikan bahwa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell 3 a with rightwards arrow on top minus b with rightwards arrow on top end cell equals cell 3 open parentheses table row 2 row 4 row 1 end table close parentheses minus open parentheses table row 8 row cell negative 2 end cell row cell negative 5 end cell end table close parentheses end cell row cell 3 a with rightwards arrow on top minus b with rightwards arrow on top end cell equals cell open parentheses table row 6 row 12 row 3 end table close parentheses minus open parentheses table row 8 row cell negative 2 end cell row cell negative 5 end cell end table close parentheses end cell row cell 3 a with rightwards arrow on top minus b with rightwards arrow on top end cell equals cell open parentheses table row cell 6 minus 8 end cell row cell 12 minus open parentheses negative 2 close parentheses end cell row cell 3 minus open parentheses negative 5 close parentheses end cell end table close parentheses end cell row cell 3 a with rightwards arrow on top minus b with rightwards arrow on top end cell equals cell open parentheses table row cell negative 2 end cell row 14 row 8 end table close parentheses end cell row cell 3 a with rightwards arrow on top minus b with rightwards arrow on top end cell equals cell 2 open parentheses table row cell negative 1 end cell row 7 row 4 end table close parentheses end cell row cell 3 a with rightwards arrow on top minus b with rightwards arrow on top end cell equals cell 2 c with rightwards arrow on top end cell end table end style

Sehingga begin mathsize 14px style 3 a with rightwards arrow on top minus b with rightwards arrow on top equals 2 c with rightwards arrow on top end style. Maka k = 2.

Akibatnya didapatkan bahwa

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell k a with rightwards arrow on top end cell equals cell 2 a with rightwards arrow on top end cell row blank equals cell 2 open parentheses table row 2 row 4 row 1 end table close parentheses end cell row blank equals cell open parentheses table row 4 row 8 row 2 end table close parentheses end cell row blank equals cell 4 i with rightwards arrow on top plus 8 j with rightwards arrow on top plus 2 k with rightwards arrow on top end cell end table end style  

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Jika titik P ( 3 , 4 , 5 ) , Q ( 7 , 2 k + 2 , 3 ) , dan R ( 1 , 7 , 6 ) terletak segaris, maka nilai dari k adalah ....

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