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Diketahui f ( x ) = 4 x + 7 dan g ( x ) = 3 x − 11 . Jika fungsi ( f ∘ g ) − 1 = ( x ) adalah ....

Diketahui  dan . Jika fungsi  adalah ....

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R. Novianto

Master Teacher

Mahasiswa/Alumni Universitas Tanjungpura Pontianak

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Kita cari nilai komposisi terlebih dahulu selanjutnya kita tentukan nilai invers komposisi jadifungsi dari dan adalah

Kita cari nilai komposisi begin mathsize 14px style open parentheses straight f ring operator straight g close parentheses open parentheses straight x close parentheses end style terlebih dahulu 
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row cell open parentheses straight f ring operator straight g close parentheses open parentheses straight x close parentheses end cell equals cell straight f open parentheses straight g open parentheses straight x close parentheses close parentheses end cell row blank equals cell 4 open parentheses straight g open parentheses straight x close parentheses close parentheses plus 7 end cell row blank equals cell 4 open parentheses 3 straight x minus 11 close parentheses plus 7 end cell row blank equals cell 12 straight x minus 44 plus 7 end cell row blank equals cell 12 straight x minus 37 end cell end table end style 
 

selanjutnya kita tentukan nilai invers komposisi begin mathsize 14px style open parentheses straight f ring operator straight g close parentheses to the power of negative 1 end exponent open parentheses straight x close parentheses end style
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 2px end attributes row straight y equals cell open parentheses straight f ring operator straight g close parentheses open parentheses straight x close parentheses equals 12 straight x minus 37 end cell row straight y equals cell 12 straight x minus 37 end cell row cell negative 12 straight x end cell equals cell negative 37 minus straight y end cell row straight x equals cell fraction numerator negative 37 minus straight y over denominator negative 12 end fraction end cell row straight x equals cell fraction numerator 37 plus straight y over denominator 12 end fraction end cell row cell straight f to the power of negative 1 end exponent open parentheses straight y close parentheses end cell equals cell fraction numerator 37 plus straight y over denominator 12 end fraction end cell row cell straight f to the power of negative 1 end exponent open parentheses x close parentheses end cell equals cell fraction numerator 37 plus straight x over denominator 12 end fraction end cell end table end style  
 

jadi fungsi begin mathsize 14px style open parentheses straight f ring operator straight g close parentheses to the power of negative 1 end exponent equals open parentheses straight x close parentheses end style dari  begin mathsize 14px style straight f open parentheses straight x close parentheses equals 4 straight x plus 7 end style dan begin mathsize 14px style straight g open parentheses straight x close parentheses equals 3 straight x minus 11 end style adalah begin mathsize 14px style fraction numerator 37 plus x over denominator 12 end fraction end style 

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Diketahui fungsi f : R → R dan g : R → R dirumuskan oleh f ( x ) = x − 2 2 x + 1 ​ , x  = 2 dan g ( x ) = x + 3 . Jika h ( x ) = ( f ∘ g ) ( x ) . Tentukanlah invers h ( x ) .

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