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Diketahui a ⇀ = 3 j − 2 k : b ⇀ = 4 i − 2 j + k dan c ⇀ = 5 i + j + 2 k . Hitunglah 2 a ⇀ ⋅ ( b ⇀ − c ⇀ ) .

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R. RGFLLIMA

Master Teacher

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Pembahasan

Operasi dot product (operasi titik)pada vektor. Untuk memudahkan kita ubah vektor di atas menjadi bentuk kotak sehingga diperoleh : Dengan operasi dot product diperoleh : Jadiii,

Operasi dot product (operasi titik) pada vektor.

Untuk memudahkan kita ubah vektor di atas menjadi bentuk kotak sehingga diperoleh :

table attributes columnalign right center left columnspacing 0px end attributes row cell straight a with rightwards harpoon with barb upwards on top end cell equals cell open parentheses table row 0 row 3 row cell negative 2 end cell end table close parentheses end cell row cell 2 straight a with rightwards harpoon with barb upwards on top end cell equals cell open parentheses table row cell 2 cross times 0 end cell row cell 2 cross times 3 end cell row cell 2 cross times left parenthesis negative 2 right parenthesis end cell end table close parentheses end cell row blank equals cell open parentheses table row 0 row 6 row cell negative 4 right parenthesis end cell end table close parentheses end cell end table 

table attributes columnalign right center left columnspacing 0px end attributes row cell straight b with rightwards harpoon with barb upwards on top end cell equals cell open parentheses table row 4 row cell negative 2 end cell row 1 end table close parentheses end cell row cell straight c with rightwards harpoon with barb upwards on top end cell equals cell open parentheses table row 5 row 1 row 2 end table close parentheses end cell row cell straight b with rightwards harpoon with barb upwards on top minus straight c with rightwards harpoon with barb upwards on top end cell equals cell open parentheses table row 4 row cell negative 2 end cell row 1 end table close parentheses minus open parentheses table row 5 row 1 row 2 end table close parentheses end cell row blank equals cell open parentheses table row cell negative 1 end cell row cell negative 3 end cell row cell negative 1 end cell end table close parentheses end cell end table 

Dengan operasi dot product diperoleh :

table attributes columnalign right center left columnspacing 0px end attributes row cell 2 straight a with rightwards harpoon with barb upwards on top times left parenthesis straight b with rightwards harpoon with barb upwards on top minus straight c with rightwards harpoon with barb upwards on top right parenthesis end cell equals cell open parentheses table row 0 row 6 row cell negative 4 end cell end table close parentheses times open parentheses table row cell negative 1 end cell row cell negative 3 end cell row cell negative 1 end cell end table close parentheses end cell row blank equals cell left parenthesis 0 right parenthesis left parenthesis negative 1 right parenthesis plus left parenthesis 6 right parenthesis left parenthesis negative 3 right parenthesis plus left parenthesis negative 4 right parenthesis left parenthesis negative 1 right parenthesis end cell row blank equals cell 0 plus left parenthesis negative 18 right parenthesis plus 4 end cell row blank equals cell negative 14 end cell end table 

Jadiii, table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 2 straight a with rightwards harpoon with barb upwards on top times left parenthesis straight b with rightwards harpoon with barb upwards on top minus straight c with rightwards harpoon with barb upwards on top right parenthesis end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank minus end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank 14 end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank. end table 

 

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