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Diketahui  dan . Hasil dari  adalah ....

Pertanyaan

Diketahui straight u with bar on top equals open parentheses table row 2 row 3 end table close parentheses dan straight v with bar on top equals open parentheses table row cell negative 5 end cell row 2 end table close parentheses. Hasil dari straight u with bar on top minus straight v with bar on top adalah ....

  1. negative 6 

  2. negative 4 

  3. 2 

  4. 4 

  5. 5 

Pembahasan Soal:

Selisih dua vektor  straight u with bar on top equals open parentheses table row 2 row 3 end table close parentheses dan straight v with bar on top equals open parentheses table row cell negative 5 end cell row 2 end table close parentheses adalah:

table attributes columnalign right center left columnspacing 0px end attributes row cell straight u with bar on top minus straight v with bar on top end cell equals cell open parentheses table row 2 row 3 end table close parentheses minus open parentheses table row cell negative 5 end cell row 2 end table close parentheses end cell row blank equals cell open parentheses table row cell 2 plus 5 end cell row cell 3 minus 2 end cell end table close parentheses end cell row blank equals cell open parentheses table row 7 row 1 end table close parentheses end cell end table

Dengan demikian, hasil dari straight u with bar on top minus straight v with bar on top adalah open parentheses table row 7 row 1 end table close parentheses.

Oleh karena itu, tidak ada jawaban yang benar.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

D. Nuryani

Mahasiswa/Alumni Universitas Padjadjaran

Terakhir diupdate 07 Juni 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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Pertanyaan yang serupa

Hasil operasi vektor  adalah ...

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses table row cell negative 4 end cell row 7 end table close parentheses minus open parentheses table row cell negative 3 end cell row cell negative 5 end cell end table close parentheses plus open parentheses table row cell negative 6 end cell row 2 end table close parentheses end cell equals cell open parentheses table row cell negative 4 minus left parenthesis negative 3 right parenthesis plus left parenthesis negative 6 right parenthesis end cell row cell 7 minus left parenthesis negative 5 right parenthesis plus 2 end cell end table close parentheses end cell row blank equals cell open parentheses table row cell negative 7 end cell row 14 end table close parentheses end cell end table end style 

Jadi, jawaban yang tepat adalah B.

0

Roboguru

Diketahui vektor dan searah. (i) (ii) (iii) Pernyataan yang benar adalah

Pembahasan Soal:

Karena vektor begin mathsize 14px style straight u with rightwards arrow on top space dan space straight v with rightwards arrow on top end style searah, maka berlaku penjumlahan vektor begin mathsize 14px style open vertical bar straight u with rightwards arrow on top plus straight v with rightwards arrow on top close vertical bar equals open vertical bar straight u with rightwards arrow on top close vertical bar plus open vertical bar straight v with rightwards arrow on top close vertical bar end style. Untuk yang pengurangan vektor hanya berlaku jika vektor berlawanan arah.

Jadi, jawaban yang tepat adalah A.

0

Roboguru

Diketahui  merupakan jajargenjang,  titik potong antara diagonalnya.   a. Sederhanakanlah: (i)   (ii)   (iii)   (iv)

Pembahasan Soal:

(i) begin mathsize 14px style QP with rightwards arrow on top plus QR with rightwards arrow on top end stylebegin mathsize 14px style equals QP with rightwards arrow on top plus PS with rightwards arrow on top equals QS with rightwards arrow on top end style  
 

(ii) begin mathsize 14px style PQ with rightwards arrow on top plus PS with rightwards arrow on top plus RS with rightwards arrow on top plus SQ with rightwards arrow on top end style

begin mathsize 14px style open parentheses PQ with rightwards arrow on top plus PS with rightwards arrow on top close parentheses plus open parentheses RS with rightwards arrow on top plus SQ with rightwards arrow on top close parentheses equals open parentheses PQ with rightwards arrow on top plus QR with rightwards arrow on top close parentheses plus RQ with rightwards arrow on top equals PR with rightwards arrow on top plus RQ with rightwards arrow on top equals PQ with rightwards arrow on top end style 
 

(iii) begin mathsize 14px style SO with rightwards arrow on top minus QO with rightwards arrow on top end style 

begin mathsize 14px style stack S O with rightwards arrow on top equals stack O Q with rightwards arrow on top stack S O with rightwards arrow on top equals negative stack Q O with rightwards arrow on top stack S O with rightwards arrow on top minus stack Q O with rightwards arrow on top equals stack S O with rightwards arrow on top minus left parenthesis negative stack S O with rightwards arrow on top right parenthesis equals 2 stack S O with rightwards arrow on top end style 


(iv) begin mathsize 14px style PR with rightwards arrow on top minus SR with rightwards arrow on top plus SQ with rightwards arrow on top end style 

begin mathsize 14px style PR with rightwards arrow on top minus SR with rightwards arrow on top plus SQ with rightwards arrow on top equals PS with rightwards arrow on top plus SQ with rightwards arrow on top equals PQ with rightwards arrow on top end style 

 

 

0

Roboguru

Diketahui titik-titik . Jika  merupakan vektor posisi dari titik A dan  merupakan vektor posisi dari titik B, tentukan .

Pembahasan Soal:

Tentukan vektor begin mathsize 14px style straight a with rightwards arrow on top end style

begin mathsize 14px style straight a with rightwards arrow on top equals negative 2 straight i with rightwards arrow on top plus 5 straight j with rightwards arrow on top end style

Tentukan vektor begin mathsize 14px style straight b with rightwards arrow on top end style

begin mathsize 14px style straight b with rightwards arrow on top equals 2 straight i with rightwards arrow on top minus straight j with rightwards arrow on top end style

Tentukan begin mathsize 14px style 2 straight a with rightwards arrow on top minus straight b with rightwards arrow on top end style

begin mathsize 14px style 2 straight a with rightwards arrow on top minus straight b with rightwards arrow on top equals 2 left parenthesis negative 2 straight i with rightwards arrow on top plus 5 straight j with rightwards arrow on top right parenthesis minus left parenthesis 2 straight i with rightwards arrow on top minus straight j with rightwards arrow on top right parenthesis 2 straight a with rightwards arrow on top minus straight b with rightwards arrow on top equals left parenthesis negative 4 straight i with rightwards arrow on top plus 10 straight j with rightwards arrow on top right parenthesis minus left parenthesis 2 straight i with rightwards arrow on top minus straight j with rightwards arrow on top right parenthesis 2 straight a with rightwards arrow on top minus straight b with rightwards arrow on top equals negative 6 straight i with rightwards arrow on top plus 11 straight j with rightwards arrow on top end style

Jadi, begin mathsize 14px style 2 straight a with rightwards arrow on top minus straight b with rightwards arrow on top equals negative 6 straight i with rightwards arrow on top plus 11 straight j with rightwards arrow on top end style.

0

Roboguru

Diketahui . Jika koordinat titik , maka koordinat titik  adalah ....

Pembahasan Soal:

Diketahui begin mathsize 14px style PQ with rightwards arrow on top equals open parentheses table row cell negative 2 end cell row cell negative 1 end cell end table close parentheses end style dan koordinat titik begin mathsize 14px style straight P open parentheses 4 comma space minus 3 close parentheses end style, maka:

begin mathsize 14px style space space space space space space space space space space space PQ with rightwards arrow on top equals straight q with rightwards arrow on top minus straight p with rightwards arrow on top space space space space space space open parentheses table row cell negative 2 end cell row cell negative 1 end cell end table close parentheses equals straight q with rightwards arrow on top minus open parentheses table row 4 row cell negative 3 end cell end table close parentheses straight q with rightwards arrow on top minus open parentheses table row 4 row cell negative 3 end cell end table close parentheses equals open parentheses table row cell negative 2 end cell row cell negative 1 end cell end table close parentheses space space space space space space space space space space space space space straight q with rightwards arrow on top equals open parentheses table row cell negative 2 end cell row cell negative 1 end cell end table close parentheses plus open parentheses table row 4 row cell negative 3 end cell end table close parentheses space space space space space space space space space space space space space straight q with rightwards arrow on top equals open parentheses table row 2 row cell negative 4 end cell end table close parentheses end style 

Jadi, jawaban yang benar adalah E.

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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