Roboguru

Diketahui  dan , bentuk sederhana  adalah ....

Diketahui begin mathsize 14px style x not equal to 0 end style dan begin mathsize 14px style y not equal to 0 end style, bentuk sederhana begin mathsize 14px style open parentheses fraction numerator 27 x to the power of negative 5 end exponent y to the power of negative 3 end exponent over denominator 3 to the power of 5 x to the power of negative 7 end exponent y to the power of negative 5 end exponent end fraction close parentheses to the power of negative 1 end exponent end style adalah ....space 

  1. begin mathsize 14px style open parentheses 3 x y close parentheses squared end style 

  2. begin mathsize 14px style 3 open parentheses x y close parentheses squared end style 

  3. begin mathsize 14px style 3 over open parentheses x y close parentheses squared end style 

  4. begin mathsize 14px style 9 open parentheses x y close parentheses squared end style 

  5. begin mathsize 14px style 9 over open parentheses x y close parentheses squared end style 

Jawaban:

Menggunakan konsep bilangan berpangkat, dapat diperoleh

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 27 x to the power of negative 5 end exponent y to the power of negative 3 end exponent over denominator 3 to the power of 5 x to the power of negative 7 end exponent y to the power of negative 5 end exponent end fraction close parentheses to the power of negative 1 end exponent end cell equals cell open parentheses fraction numerator 3 cubed x to the power of negative 5 end exponent y to the power of negative 3 end exponent over denominator 3 to the power of 5 x to the power of negative 7 end exponent y to the power of negative 5 end exponent end fraction close parentheses to the power of negative 1 end exponent end cell row blank equals cell open parentheses 3 to the power of 3 minus 5 end exponent x to the power of negative 5 minus left parenthesis negative 7 right parenthesis end exponent y to the power of negative 3 minus left parenthesis negative 5 right parenthesis end exponent close parentheses to the power of negative 1 end exponent end cell row blank equals cell open parentheses 3 to the power of negative 2 end exponent x squared y squared close parentheses to the power of negative 1 end exponent end cell row blank equals cell 3 to the power of left parenthesis negative 2 right parenthesis cross times left parenthesis negative 1 right parenthesis end exponent x to the power of 2 cross times left parenthesis negative 1 right parenthesis end exponent y to the power of 2 cross times left parenthesis negative 1 right parenthesis end exponent end cell row blank equals cell 3 squared x to the power of negative 2 end exponent y to the power of negative 2 end exponent end cell row blank equals cell fraction numerator 3 squared over denominator x squared y squared end fraction end cell row blank equals cell 9 over open parentheses x y close parentheses squared end cell end table end style

Jadi,  jawaban yang tepat adalah E.space  

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