Pertanyaan

Diketahui , f ( 1 ) = …

Diketahui f open parentheses x close parentheses equals blank 3 cube root of x plus 2 x , $f (1) = \dots$

M. Iqbal

Master Teacher

Mahasiswa/Alumni Universitas Negeri Semarang

Jawaban terverifikasi

Jawaban

hasil dari fungsi adalah 3.

hasil dari f to the power of apostrophe left parenthesis 1 right parenthesis

fungsi

f open parentheses x close parentheses equals 3 cube root of x plus 2 x

adalah 3.

Pembahasan

Ingat rumus turunan . Pertama ubah terlebih dahulu fungsi menjadi bentuk lain Sehingga Selanjutnya substitusi 1 ke fungsi Jadi, hasil dari fungsi adalah 3.

Ingat rumus turunan y equals a times x to the power of n rightwards arrow y to the power of apostrophe equals a times n times x to the power of n minus 1 end exponent . Pertama ubah terlebih dahulu fungsi f left parenthesis x right parenthesis menjadi bentuk lain

table attributes columnalign right center left columnspacing 0px end attributes row cell f open parentheses x close parentheses end cell equals cell 3 cube root of x plus 2 x end cell row cell f open parentheses x close parentheses end cell equals cell 3 x to the power of 1 third end exponent plus 2 x end cell end table

Sehingga

$table attributes columnalign right center left columnspacing 0px end attributes row cell f open parentheses x close parentheses end cell equals cell 3 x to the power of 1 third end exponent plus 2 x end cell row cell f apostrophe open parentheses x close parentheses end cell equals cell 3 times 1 third times x to the power of 1 third minus 1 end exponent plus 2 end cell row blank equals cell x to the power of negative 2 over 3 end exponent plus 2 end cell row blank equals cell fraction numerator 1 over denominator cube root of x squared end root end fraction plus 2 end cell end table$

Selanjutnya substitusi 1 ke fungsi f apostrophe left parenthesis x right parenthesis

$table attributes columnalign right center left columnspacing 0px end attributes row cell f apostrophe open parentheses x close parentheses end cell equals cell fraction numerator 1 over denominator cube root of x squared end root end fraction plus 2 end cell row cell f apostrophe open parentheses 1 close parentheses end cell equals cell fraction numerator 1 over denominator cube root of 1 squared end root end fraction plus 2 end cell row blank equals cell fraction numerator 1 over denominator cube root of 1 end fraction plus 2 end cell row blank equals cell 1 over 1 plus 2 end cell row blank equals cell 1 plus 2 end cell row blank equals 3 end table$

Jadi, hasil dari f to the power of apostrophe left parenthesis 1 right parenthesis fungsi f open parentheses x close parentheses equals 3 cube root of x plus 2 x adalah 3.