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digunakan dalam produksi kaca hias yang tampak berbeda warna jika dilihat dari sudut yang berbeda. merupakan garam dengan kelarutan yang rendah (). a. Tentukan kelarutan molar  dalam air.

Pertanyaan

Pb Cl subscript 2 digunakan dalam produksi kaca hias yang tampak berbeda warna jika dilihat dari sudut yang berbeda. Pb Cl subscript 2merupakan garam dengan kelarutan yang rendah (K subscript sp equals 1 comma 6 cross times 10 to the power of negative sign 5 end exponent).

a. Tentukan kelarutan molar Pb Cl subscript 2 dalam air.

Pembahasan Soal:

Pb Cl subscript 2 equilibrium Pb to the power of 2 plus sign and 2 Cl to the power of minus sign space space space space s space space space space space space space space space space s space space space space space space space space 2 s 

table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space Pb Cl subscript 2 end cell equals cell open square brackets Pb to the power of 2 plus sign close square brackets open curly brackets Cl to the power of minus sign close square brackets squared end cell row cell 1 comma 6 cross times 10 to the power of negative sign 5 end exponent end cell equals cell open parentheses s close parentheses left parenthesis 2 s right parenthesis squared end cell row cell 1 comma 6 cross times 10 to the power of negative sign 5 end exponent end cell equals cell 4 s cubed end cell row cell s cubed end cell equals cell fraction numerator 1 comma 6 cross times 10 to the power of negative sign 5 end exponent over denominator 4 end fraction end cell row s equals cell cube root of 4 cross times 10 to the power of negative sign 6 end exponent end root end cell row s equals cell 1 comma 59 cross times 10 to the power of negative sign 2 end exponent end cell end table  


Jadi, kelarutan molar PbCl2 dalam air sebesar bottom enclose bold 1 bold comma bold 59 bold cross times bold 10 to the power of bold minus sign bold 2 end exponent bold. end enclose 

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

S. Hidayati

Mahasiswa/Alumni Universitas Indonesia

Terakhir diupdate 05 Juni 2021

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Pertanyaan yang serupa

Suatu larutan  sebanyak 0,074 gram mempunyai  dalam 100 mL air.  atom X adalah ....

Pembahasan Soal:

Error converting from MathML to accessible text. 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp space X open parentheses O H close parentheses subscript 2 end cell equals cell open square brackets X to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell row cell 4 cross times 10 to the power of negative sign 6 end exponent end cell equals cell open parentheses s close parentheses left parenthesis 2 s right parenthesis squared end cell row cell 4 cross times 10 to the power of negative sign 6 end exponent end cell equals cell 4 s cubed end cell row s equals cell cube root of fraction numerator 4 cross times 10 to the power of negative sign 6 end exponent over denominator 4 end fraction end root end cell row s equals cell 10 to the power of negative sign 2 end exponent space M end cell end table end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row s equals cell m over M subscript r cross times fraction numerator 1.000 over denominator V end fraction end cell row cell 10 to the power of negative sign 2 end exponent end cell equals cell fraction numerator 0 comma 074 over denominator M subscript r end fraction cross times fraction numerator 1.000 over denominator 100 end fraction end cell row cell 10 to the power of negative sign 2 end exponent end cell equals cell fraction numerator 0 comma 74 over denominator M subscript r end fraction end cell row cell M subscript r end cell equals cell fraction numerator 0 comma 74 over denominator 10 to the power of negative sign 2 end exponent end fraction end cell row cell M subscript r end cell equals 74 end table end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell M subscript r space X open parentheses O H close parentheses subscript 2 end cell equals cell left parenthesis 1 cross times A subscript r space X right parenthesis plus left parenthesis 2 cross times A subscript r space O right parenthesis plus left parenthesis 2 cross times A subscript r space H right parenthesis end cell row 74 equals cell A subscript r space X plus left parenthesis 2 cross times 16 right parenthesis plus left parenthesis 2 cross times 1 right parenthesis end cell row 74 equals cell A subscript r space X plus 34 end cell row cell A subscript r space X end cell equals cell 74 minus sign 34 end cell row cell A subscript r space X end cell equals 40 end table end style 


Jadi, massa atom relatif atom X adalah 40.

Roboguru

Pada suhu . Hitunglah kelarutan pada larutan 0,001 M.

Pembahasan Soal:

Persamaan reaksi yang terjadi adalah


Ni open parentheses O H close parentheses subscript 2 left parenthesis italic a italic q right parenthesis equilibrium Ni to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus 2 O H to the power of minus sign left parenthesis italic a italic q right parenthesis Ni Cl subscript 2 left parenthesis italic a italic q right parenthesis equilibrium Ni to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus 2 Cl to the power of minus sign left parenthesis italic a italic q right parenthesis


Misalkan kelarutan Ni open parentheses O H close parentheses subscript 2 dalam Ni Cl subscript 2 adalah s mol/liter, maka di dalam sistem terdapat:

  • open square brackets Ni to the power of 2 plus sign close square brackets equals open parentheses 10 to the power of negative sign 3 end exponent plus s close parentheses space mol forward slash L
  • open square brackets O H to the power of minus sign close square brackets equals 2 s space mol forward slash L

Oleh karena ion Ni dari Ni open parentheses O H close parentheses subscript 2 jauh lebih kecil dari ion Ni dari Ni Cl subscript 2, maka besarnya ion Ni dari Ni open parentheses O H close parentheses subscript 2 dapat diabaikan.


table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Ni to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell open parentheses 10 to the power of negative sign 3 end exponent close parentheses cross times open parentheses 2 s close parentheses squared end cell row s equals cell 3 comma 87 cross times 10 to the power of negative sign 8 end exponent space mol forward slash L end cell end table


Jadi, kelarutannya adalah bold 3 bold comma bold 87 bold cross times bold 10 to the power of bold minus sign bold 8 end exponent mol/L.space

Roboguru

Kelarutan  di dalam  adalah . Hitunglah .

Pembahasan Soal:

begin mathsize 14px style Na I O subscript 3 left parenthesis italic a italic q right parenthesis equilibrium Na to the power of plus sign left parenthesis italic a italic q right parenthesis plus I O subscript 3 to the power of minus sign left parenthesis italic a italic q right parenthesis space space space space 0 comma 1 space M space space space space space space space space space space 0 comma 1 space M space space space space space space space 0 comma 1 space M end style   

 

begin mathsize 14px style Pb open parentheses I O subscript 3 close parentheses subscript 2 left parenthesis italic s right parenthesis equilibrium Pb to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus 2 I O subscript 3 to the power of minus sign left parenthesis italic a italic q right parenthesis space space space space space space space space italic s space space space space space space space space space space space space space space space space space space italic s space space space space space space space space space space space space space space 2 italic s end style 

 

Error converting from MathML to accessible text.     

Jadi, begin mathsize 14px style K subscript sp italic space Pb open parentheses I O subscript 3 close parentheses subscript 2 equals 2 comma 4 cross times 10 to the power of negative sign 13 end exponent end styleundefined

Roboguru

Pada suhu . Hitunglah kelarutan pada larutan 0,01 M.

Pembahasan Soal:

Persamaan reaksi yang terjadi adalah


Ni open parentheses O H close parentheses subscript 2 left parenthesis italic a italic q right parenthesis equilibrium Ni to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus 2 O H to the power of minus sign left parenthesis italic a italic q right parenthesis K O H left parenthesis italic a italic q right parenthesis equilibrium K to the power of plus sign left parenthesis italic a italic q right parenthesis plus O H to the power of minus sign left parenthesis italic a italic q right parenthesis


Misalkan kelarutan Ni open parentheses O H close parentheses subscript 2 dalam K O H adalah s mol/L, maka pada sistem terdapat:

  • open square brackets Ni to the power of 2 plus sign close square brackets equals s space mol forward slash L
  • open square brackets O H to the power of minus sign close square brackets equals open parentheses 0 comma 01 plus 2 s close parentheses space mol forward slash L

Oleh karena open square brackets O H to the power of minus sign close square brackets dari Ni open parentheses O H close parentheses subscript 2 jauh lebih kecil daripada besarnya open square brackets O H to the power of minus sign close square brackets dari K O H, maka open square brackets O H to the power of minus sign close square brackets dari Ni open parentheses O H close parentheses subscript 2 dapat diabaikan.


table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Ni to the power of 2 plus sign close square brackets open square brackets O H to the power of minus sign close square brackets squared end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell s cross times open parentheses 0 comma 01 close parentheses squared end cell row s equals cell 6 cross times 10 to the power of negative sign 14 end exponent space mol forward slash L end cell end table


Jadi, kelarutannya adalah bold 6 bold cross times bold 10 to the power of bold minus sign bold 14 end exponent mol/liter.space

Roboguru

Pada suhu , . Hitunglah kelarutan  pada : a.  larutan  0,001 M, b.  larutan  0,001 M, c.  larutan yang mempunyai pH = 11, d.  larutan yang berisi  0,1 M dan  0,1 M

Pembahasan Soal:

begin mathsize 14px style Ni open parentheses O H close parentheses subscript 2 yields Ni to the power of 2 plus sign and 2 O H to the power of minus sign end style 


Dalam larutan jenuh begin mathsize 14px style Ni open parentheses O H close parentheses subscript 2 end style terdapat kesetimbangan 


begin mathsize 14px style Ni open parentheses O H close parentheses subscript 2 yields Ni to the power of 2 plus sign and 2 O H to the power of minus sign space space space space space space S space space space space space space space space space space space S space space space space space space space space 2 S end style 


Maka harga Ksp nya dinyatakan dalam :


Error converting from MathML to accessible text. 


a)  Penambahan 0,001 M NaOH

begin mathsize 14px style Na O H yields Na to the power of plus sign and O H to the power of minus sign 0 comma 001 space space space 0 comma 001 space space 0 comma 001 end style   


begin mathsize 14px style open square brackets ion space sejenis close square brackets equals open square brackets O H to the power of minus sign close square brackets equals 0 comma 001 equals 10 to the power of negative sign 3 end exponent end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Ni to the power of 2 plus sign close square brackets middle dot open square brackets 2 O H to the power of minus sign close square brackets end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell S middle dot open square brackets 10 to the power of negative sign 3 end exponent close square brackets squared end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell S middle dot 10 to the power of negative sign 6 end exponent end cell row S equals cell 6 cross times 10 to the power of negative sign 12 end exponent space M end cell end table end style 


Jadi, kelarutan dalam 0,001 M NaOH adalah begin mathsize 14px style 6 cross times 10 to the power of negative sign 12 end exponent space M end style 

b)  Penambahan 0,001 M begin mathsize 14px style Ni Cl subscript 2 end style 


begin mathsize 14px style Ni Cl subscript 2 yields Ni to the power of 2 plus sign and 2 Cl to the power of minus sign 0 comma 001 space space space 0 comma 001 space space 0 comma 002 end style 


begin mathsize 14px style open square brackets ion space sejenis close square brackets equals open square brackets Ni to the power of 2 plus sign close square brackets equals 0 comma 001 equals 10 to the power of negative sign 3 end exponent end style 


 begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Ni to the power of 2 plus sign close square brackets middle dot open square brackets 2 O H to the power of minus sign close square brackets end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell 10 to the power of negative sign 3 end exponent middle dot open parentheses 2 S close parentheses squared end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell 10 to the power of negative sign 3 end exponent middle dot 4 S squared end cell row cell 6 cross times 10 to the power of negative sign 15 end exponent end cell equals cell 4 S squared end cell row cell S squared end cell equals cell 1 comma 5 cross times 10 to the power of negative sign 15 end exponent end cell row S equals cell 3 comma 87 cross times 10 to the power of negative sign 8 end exponent space M end cell end table end style 


Jadi, kelarutan dalam 0,001 M undefined adalah begin mathsize 14px style 3 comma 87 cross times 10 to the power of negative sign 8 end exponent space M end style.

c)  Penambahan larutan pH 11


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals 11 row pOH equals 3 row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell 10 to the power of negative sign 3 end exponent space M end cell end table end style 


begin mathsize 14px style open square brackets ion space sejenis close square brackets equals open square brackets O H to the power of minus sign close square brackets equals 0 comma 001 equals 10 to the power of negative sign 3 end exponent end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Ni to the power of 2 plus sign close square brackets middle dot open square brackets 2 O H to the power of minus sign close square brackets end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell S middle dot open square brackets 10 to the power of negative sign 3 end exponent close square brackets squared end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell S middle dot 10 to the power of negative sign 6 end exponent end cell row S equals cell 6 cross times 10 to the power of negative sign 12 end exponent space M end cell end table end style 


Jadi, kelarutan dalam larutan pH 11 adalah begin mathsize 14px style 6 cross times 10 to the power of negative sign 12 end exponent space M end style.

d)  Penambahan larutan larutan yang berisi begin mathsize 14px style N H subscript 3 end style 0,1 M dan begin mathsize 14px style N H subscript 4 Cl end style 0,1 M undefined


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets O H to the power of minus sign close square brackets end cell equals cell Kb cross times fraction numerator open square brackets basa space lemah close square brackets over denominator open square brackets garam close square brackets end fraction end cell row blank equals cell 10 to the power of negative sign 5 end exponent cross times 1 over 1 end cell row blank equals cell 10 to the power of negative sign 5 end exponent space M end cell end table end style 


begin mathsize 14px style open square brackets ion space sejenis close square brackets equals open square brackets O H to the power of minus sign close square brackets equals open square brackets 10 to the power of negative sign 5 end exponent close square brackets end style 


begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript sp end cell equals cell open square brackets Ni to the power of 2 plus sign close square brackets middle dot open square brackets 2 O H to the power of minus sign close square brackets end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell S middle dot open square brackets 10 to the power of negative sign 5 end exponent close square brackets squared end cell row cell 6 cross times 10 to the power of negative sign 18 end exponent end cell equals cell S middle dot 10 to the power of negative sign 10 end exponent end cell row S equals cell 6 cross times 10 to the power of negative sign 8 end exponent space M end cell end table end style 


Jadi, kelarutan dalam larutan penyangga adalah begin mathsize 14px style 6 cross times 10 to the power of negative sign 8 end exponent space M end style.

Roboguru

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