Pertanyaan

Diberikan f ( x ) = x 2 + 2 dan g ( x ) = x 1 , x  = 0 . Tentukan: b. g ∘ f

Diberikan $f (x) = x^{2} + 2$ dan $g (x) = \frac{1}{x}, x \neq = 0$ . Tentukan:

b. $g \circ f$

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$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell left parenthesis g ring operator f right parenthesis end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell left parenthesis x right parenthesis end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 1 over denominator x squared plus 2 end fraction end cell end table end style$ .

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$begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses g ring operator f close parentheses open parentheses x close parentheses end cell equals cell g open parentheses f open parentheses x close parentheses close parentheses end cell row blank equals cell g open parentheses x squared plus 2 close parentheses end cell row blank equals cell fraction numerator 1 over denominator x squared plus 2 end fraction end cell end table end style$

Jadi, $begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell left parenthesis g ring operator f right parenthesis end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell left parenthesis x right parenthesis end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank equals blank end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator 1 over denominator x squared plus 2 end fraction end cell end table end style$ .