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Data percobaan untuk reaksi adalah sebagai berikut: Orde reaksi terhadap A dan B berturut-turut adalah ....

Pertanyaan

Data percobaan untuk reaksi A and B yields AB adalah sebagai berikut:

Orde reaksi terhadap A dan B berturut-turut adalah ....space

  1. 2 dan 4space

  2. 2 dan 2space

  3. 2 dan 1space

  4. 1 dan 2space

  5. 1 dan 1space

Pembahasan Soal:

Menghitung orde terhadap reaktan A

table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 over v subscript 2 end cell equals cell fraction numerator k space open square brackets A close square brackets to the power of a open square brackets B close square brackets to the power of b over denominator k space open square brackets A close square brackets to the power of a open square brackets B close square brackets to the power of b end fraction end cell row cell 20 over 180 end cell equals cell fraction numerator open square brackets 0 comma 1 close square brackets to the power of a open square brackets 0 comma 05 close square brackets to the power of b over denominator open square brackets 0 comma 3 close square brackets to the power of a open square brackets 0 comma 05 close square brackets to the power of b end fraction end cell row cell 1 over 9 end cell equals cell open square brackets 0 comma 1 close square brackets to the power of a over open square brackets 0 comma 3 close square brackets to the power of a end cell row cell 1 over 9 end cell equals cell left parenthesis 1 third right parenthesis to the power of a space end cell row a equals 2 end table

Menghitung orde terhadap reaktan B

table attributes columnalign right center left columnspacing 0px end attributes row cell v subscript 1 over v subscript 3 end cell equals cell fraction numerator k space open square brackets A close square brackets to the power of a open square brackets B close square brackets to the power of b over denominator k space open square brackets A close square brackets to the power of a open square brackets B close square brackets to the power of b end fraction end cell row cell 20 over 320 end cell equals cell fraction numerator open square brackets 0 comma 1 close square brackets to the power of a open square brackets 0 comma 05 close square brackets to the power of b over denominator open square brackets 0 comma 1 close square brackets to the power of a open square brackets 0 comma 20 close square brackets to the power of b end fraction end cell row cell 1 over 16 end cell equals cell open square brackets 0 comma 05 close square brackets to the power of b over open square brackets 0 comma 20 close square brackets to the power of b end cell row cell 1 over 16 end cell equals cell left parenthesis 1 fourth right parenthesis to the power of b end cell row b equals 2 end table 

Jadi, orde terhadap reaktan A dan B berturut-turut adalah 2 dan 2.

Jadi, jawaban yang tepat adalah B.space

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 02 Juni 2021

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