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Pertanyaan

Dari lima macam larutan berikut,

  1. Mg Cl subscript 2 0,4 M
  2. Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 space 0,2 M
  3. C subscript 6 H subscript 12 O subscript 6 1,0 M
  4. Na N O subscript 3 0,3 M
  5. K subscript 3 P O subscript 4 0,5 M

larutan yang isotonis satu sama lain adalah ....

  1. 1,3

  2. 2,3

  3. 1,5space

  4. 2,4space 

  5. 3,5space

S. Lubis

Master Teacher

Jawaban terverifikasi

Jawaban

tidak jawaban yang tepat.

Pembahasan

Larutan isotonis adalah dua larutan yang memiliki tekanan osmosis yang sama

isotonis pi 1 equals pi 2

  • menghitung tekanan osmosis larutan Mg Cl subscript 2 space end subscript 

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell Mg Cl subscript 2 space space space 0 comma 4 space M end cell row i equals cell left parenthesis 1 plus left parenthesis n minus sign 1 right parenthesis alpha right parenthesis end cell row blank equals cell left parenthesis 1 plus left parenthesis 3 minus sign 1 right parenthesis 1 right parenthesis end cell row blank equals cell left parenthesis 1 plus 2.1 right parenthesis end cell row blank equals cell 1 plus 2 end cell row blank equals 3 row blank blank blank row pi equals cell M space R space T space i space end cell row blank equals cell 0 comma 4 space M space x space R space x space T space x space 3 end cell row blank equals cell 0 comma 12 space RT end cell end table

  • menghitung tekanan osmosis larutan Fe subscript 2 space open parentheses S O subscript 4 close parentheses subscript 3 space end subscript  

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 space 0 comma 2 space M end cell row cell Fe subscript 2 open parentheses S O subscript 4 close parentheses subscript 3 end cell rightwards arrow cell 2 Fe to the power of 3 plus sign and 3 S O subscript 4 to the power of 2 minus sign end cell row i equals cell left parenthesis 1 plus left parenthesis n minus sign 1 right parenthesis alpha right parenthesis end cell row blank equals cell left parenthesis 1 plus left parenthesis 5 minus sign 1 right parenthesis 1 right parenthesis end cell row blank equals cell left parenthesis 1 plus 4.1 right parenthesis end cell row blank equals cell 1 plus 4 end cell row blank equals 5 row pi equals cell M space R space T space i space end cell row blank equals cell 0 comma 2 space M space x space R space x space T space x space 5 end cell row blank equals cell 0 comma 10 space RT end cell end table

  • menghitung tekanan osmosis larutan C subscript 6 H subscript 12 O subscript 6 space end subscript 

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell C subscript 6 H subscript 12 O subscript 6 space 1 comma 0 space M end cell row cell C subscript 6 H subscript 12 O subscript 6 end cell rightwards arrow cell tidak space terionisasi end cell row i equals cell left parenthesis 1 plus left parenthesis 1 minus sign 1 right parenthesis i right parenthesis end cell row blank equals cell left parenthesis 1 plus left parenthesis 1 minus sign 1 right parenthesis 0 right parenthesis end cell row blank equals cell left parenthesis 1 plus 0 right parenthesis end cell row blank equals 1 row pi equals cell M space R space T space i space end cell row blank equals cell 1 comma 0 space M space x space R space x space T space x space 1 end cell row blank equals RT end table

  • menghitung tekanan osmosis larutan Na N O subscript 3 space end subscript 

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell Na N O subscript 3 space 0 comma 3 space M end cell row cell Na N O subscript 3 end cell rightwards arrow cell Na to the power of plus sign and N O subscript 3 to the power of minus sign end cell row i equals cell left parenthesis 1 plus left parenthesis n minus sign 1 right parenthesis i right parenthesis end cell row blank equals cell left parenthesis 1 plus left parenthesis 2 minus sign 1 right parenthesis 1 right parenthesis end cell row blank equals cell left parenthesis 1 plus 1 right parenthesis end cell row blank equals 2 row pi equals cell M space R space T space i space end cell row blank equals cell 0 comma 3 space M space x space R space x space T space x space 2 end cell row blank equals cell 0 comma 6 space RT end cell end table

  • menghitung tekanan osmosis larutan K subscript 3 P O subscript 4 space end subscript 

table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell K subscript 3 P O subscript 4 space 0 comma 5 space M end cell row cell K subscript 3 P O subscript 4 space end cell rightwards arrow cell 3 K to the power of plus sign and P O subscript 4 to the power of 3 minus sign end cell row i equals cell left parenthesis 1 plus left parenthesis n minus sign 1 right parenthesis i right parenthesis end cell row blank equals cell left parenthesis 1 plus left parenthesis 4 minus sign 1 right parenthesis 1 right parenthesis end cell row blank equals cell left parenthesis 1 plus 3 right parenthesis end cell row blank equals 4 row pi equals cell M space R space T space i space end cell row blank equals cell 0 comma 5 space M space x space R space x space T space x space 4 end cell row blank equals cell 2 comma 0 space RT end cell end table

 

Berdasarkan perhitungan di atas tidak ada larutan dengan  nilai pi yang sama.

Jadi, tidak jawaban yang tepat.

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Suatu larutan mempunyai tekanan osmotik sebesar 3MRT. Larutan yang sesuai dengan data tersebut adalah ....

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