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Besarnya pH larutan asam metanoat 0,01 M adalah 5. Harga tetapan asam metanoat tersebut adalah ....

Pertanyaan

Besarnya pH larutan asam metanoat 0,01 M adalah 5. Harga tetapan asam metanoat tersebut adalah ....undefined 

  1. begin mathsize 14px style 1 cross times 10 to the power of negative sign 5 end exponent end style 

  2. begin mathsize 14px style 1 cross times 10 to the power of negative sign 6 end exponent end style 

  3. begin mathsize 14px style 1 cross times 10 to the power of negative sign 7 end exponent end style 

  4. begin mathsize 14px style 1 cross times 10 to the power of negative sign 8 end exponent end style 

  5. begin mathsize 14px style 2 cross times 10 to the power of negative sign 8 end exponent end style 

Pembahasan Soal:

Asam metanoat merupakan asam lemah. Maka,

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row pH equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row 5 equals cell negative sign log space open square brackets H to the power of plus sign close square brackets end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 10 to the power of negative sign 5 end exponent end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell square root of K subscript a cross times M subscript a end root end cell row cell 10 to the power of negative sign 5 end exponent end cell equals cell square root of K subscript a cross times 0 comma 01 end root space left parenthesis kuadratkan space kedua space ruas right parenthesis end cell row cell 10 to the power of negative sign 10 end exponent end cell equals cell K subscript a cross times 10 to the power of negative sign 2 end exponent end cell row cell K subscript a end cell equals cell 10 to the power of negative sign 8 end exponent end cell end table end style 

Jadi, jawaban yang benar adalah D.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 03 April 2021

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