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Berikut beberapa garam dan Ksp nya. (1)  ,   (2) ...

Berikut beberapa garam dan Ksp nya.

(1) begin mathsize 14px style Cd C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp equals 15 x 10 to the power of negative sign 8 end exponent end style 
(2) begin mathsize 14px style Sr C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp equals 15 x 10 to the power of negative sign 7 end exponent end style 
(3) begin mathsize 14px style Pb C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp equals 8 comma 6 x 10 to the power of negative sign 10 end exponent end style 
(4) begin mathsize 14px style Zn C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp space equals 1 comma 4 space x 10 to the power of negative sign 9 end exponent end style 

Urutan kelarutan senyawa tersebut dari yang kecil ke besar adalah ....undefined

Jawaban:

Pada soal di atas diketahui beberapa data Ksp senyawa yaitu:

1) begin mathsize 14px style Cd C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp equals 15 x 10 to the power of negative sign 8 end exponent end style 
(2) begin mathsize 14px style Sr C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp equals 15 x 10 to the power of negative sign 7 end exponent end style 
(3) begin mathsize 14px style Pb C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp equals 8 comma 6 x 10 to the power of negative sign 10 end exponent end style 
(4) begin mathsize 14px style Zn C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp space equals 1 comma 4 space x 10 to the power of negative sign 9 end exponent end style 

Urutan kelarutan dari yang paling kecil ke besar dapat ditentukan menggunakan data Ksp. Kelarutan besar berarti garam lebih mudah larut. Adapun jika kelarutannya lebih kecil berarti garam lebih sukar larut. Langkah yang dapat dilakukan adalah:

  • menentukan harga kelarutan (s) melalui Ksp yang diketahui. 
  • mensubstitusikan harga Ksp untuk menentukan s dari garam tersebut.

1. begin mathsize 14px style Cd C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp equals 15 x 10 to the power of negative sign 8 end exponent end style 

begin mathsize 14px style Cd C subscript 2 O subscript 4 rightwards harpoon over leftwards harpoon end subscript Cd to the power of 2 plus sign and C subscript 2 O subscript 4 to the power of 2 minus sign s space space space space space space space space space space space space space space space s space space space space space space space space space space s Ksp double bond open square brackets Cd to the power of 2 plus sign close square brackets open square brackets C subscript 2 O subscript 4 to the power of 2 minus sign close square brackets Ksp double bond s point s Ksp equals s squared s equals square root of Ksp s equals square root of 15 x 10 to the power of negative sign 8 end exponent end root s equals 3 comma 87 space x space 10 to the power of negative sign 4 end exponent end style 

 

2. begin mathsize 14px style Sr C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp equals 15 x 10 to the power of negative sign 7 end exponent end style 

begin mathsize 14px style Sr C subscript 2 O subscript 4 equilibrium Sr to the power of 2 plus sign and C subscript 2 O subscript 4 to the power of 2 minus sign s space space space space space space space space space space space space space s space space space space space space space space space space space s Ksp double bond open square brackets Sr to the power of 2 plus sign close square brackets open square brackets C subscript 2 O subscript 4 to the power of 2 minus sign close square brackets Ksp double bond s point s Ksp equals s squared s equals square root of ksp s equals square root of 15 x 10 to the power of negative sign 7 end exponent end root s equals 1 comma 22 x 10 to the power of negative sign 4 end exponent  end style    

 

3. begin mathsize 14px style Pb C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp equals 8 comma 6 x 10 to the power of negative sign 10 end exponent end style 

begin mathsize 14px style Pb C subscript 2 O subscript 4 equilibrium Pb to the power of 2 plus sign and C subscript 2 O subscript 4 to the power of 2 minus sign s space space space space space space space space space space space space space space s space space space space space space space space space space s Ksp double bond s point s Ksp equals s squared s equals square root of Ksp s equals square root of 8 comma 6 x 10 to the power of negative sign 10 end exponent end root s equals 0 comma 293 space x 10 to the power of negative sign 4 end exponent end style   

 

4. begin mathsize 14px style Zn C subscript 2 O subscript 4 end style , begin mathsize 14px style Ksp space equals 1 comma 4 space x 10 to the power of negative sign 9 end exponent end style 

​ begin mathsize 14px style Zn C subscript 2 O subscript 4 equilibrium Zn to the power of 2 plus sign and C subscript 2 O subscript 4 to the power of 2 minus sign s space space space space space space space space space space space space space space s space space space space space space space space space space space s Ksp double bond s point s Ksp equals s squared s equals square root of Ksp s equals square root of 1 comma 4 x 10 to the power of negative sign 9 end exponent end root s equals 0 comma 374 x 10 to the power of negative sign 5 end exponent s equals 3 comma 74 x 10 to the power of negative sign 4 end exponent end style    

Berdasarkan perhitungan di atas, maka urutan kelarutan enyawa tersebut dari yang kecil ke besar adalah:

begin mathsize 14px style 0 comma 293 x 10 to the power of negative sign 4 end exponent less than 3 comma 74 x 10 to the power of negative sign 4 end exponent less than 1 comma 22 x 10 to the power of negative sign 4 end exponent 3 comma 87 x 10 to the power of negative sign 4 end exponent end style  

atau jika dituliskan menurut garamnya, kelarutan dari yang paling kecil ke besar adalah:

begin mathsize 14px style Pb C subscript 2 O subscript 4 less than Zn C subscript 2 O subscript 4 less than Sr C subscript 2 O subscript 4 less than Cd C subscript 2 O subscript 4 end style atau urutan nomornya 3,4,1,2.

Jadi, jawaban yang benar adalah C.

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