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Berapakah pH larutan jenuh jika   dan  ?

Pertanyaan

Berapakah pH larutan jenuh begin mathsize 14px style Ca C O subscript 3 end style jika begin mathsize 14px style K subscript italic s italic p end subscript italic space Ca C O subscript 3 space equals space 4 comma 8 space x space 10 to the power of negative sign 9 end exponent space end style  dan begin mathsize 14px style K subscript italic a italic space H subscript 2 C O subscript 3 space equals space 4 space x space 10 to the power of negative sign 7 end exponent end style ?

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Pembahasan Video:

Pembahasan Soal:

Diketahui bahwa K subscript italic s italic p end subscript dari Ca C O subscript 3 = 4 comma 8 cross times 10 to the power of negative sign 9 end exponent

Ca C O subscript 3 open parentheses italic s italic close parentheses space equilibrium Ca to the power of 2 plus sign left parenthesis italic a italic q right parenthesis plus space C O subscript 3 to the power of 2 minus sign end exponent left parenthesis italic a italic q right parenthesis s space space space space space space space space space space space space space space space space space space space s space space space space space space space space space space space space space space space space space space space space s  .

Mulai terbentuk endapan = K subscript italic s italic p end subscript sama dengan italic Q subscript italic s italic p end subscript

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Untuk mencaripH digunakan konsep hidrolisis karena Ca C O subscript 3 merupakan garam yang terhidrolisis sebagian dan akan menghasilkan O H to the power of minus sign . Nilai konsentrasi O H to the power of minus sign adalah:

open square brackets O H to the power of minus sign close square brackets space equals square root of Kw over Ka space x space M space left square bracket C O subscript 3 to the power of 2 minus sign end exponent right square bracket space end root open square brackets O H to the power of minus sign close square brackets space equals square root of 10 to the power of negative sign 14 end exponent over 10 space x space 6 comma 92 space x space 10 to the power of negative sign 5 end exponent end root open square brackets O H to the power of minus sign close square brackets space equals square root of fraction numerator 10 to the power of negative sign 14 end exponent over denominator 4 space x space 10 to the power of negative sign 7 end exponent end fraction space x space 6 comma 92 space x space 10 to the power of negative sign 5 end exponent end root open square brackets O H to the power of minus sign close square brackets space equals 1 comma 32 space x space 10 to the power of negative sign 6 end exponent  . 

pOH space equals 6 minus sign log space 1 comma 32 pH space equals space 14 minus sign left parenthesis 6 minus sign log space 1 comma 32 right parenthesis pH space equals space 8 plus log space 1 comma 32 

Jaka, pH Larutan jenuh adalah 8 + log 1.32 

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 18 Juli 2021

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