Roboguru

Berapa volume larutan  0,1 molar dan  0,1 molar yang diperlukan untuk membuat 100 mL larutan penyangga dengan pH 6 jika .

Pertanyaan

Berapa volume larutan undefined 0,1 molar dan begin mathsize 14px style C H subscript 3 C O O H end style 0,1 molar yang diperlukan untuk membuat 100 mL larutan penyangga dengan pH 6 jika begin mathsize 14px style K subscript a space C H subscript 3 C O O H equals 10 to the power of negative sign 5 end exponent end style.undefined 

Pembahasan Soal:

Misalnya: 

begin mathsize 14px style V space Na O H double bond x space mL end style, berarti begin mathsize 14px style V space C H subscript 3 C O O H equals 100 minus sign x space mL end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n space Na O H end cell equals cell V cross times M end cell row blank equals cell x space mL cross times 0 comma 1 space M end cell row blank equals cell 0 comma 1 x space mmol end cell end table end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell n space C H subscript 3 C O O H end cell equals cell V cross times M end cell row blank equals cell left parenthesis 100 minus sign x right parenthesis space mL cross times 0 comma 1 space M end cell row blank equals cell 10 minus sign 0 comma 1 x space mmol end cell end table end style 

Pereaksi pembatasnya adalah begin mathsize 14px style Na O H end style sehingga campuran antara begin mathsize 14px style Na O H end style dan begin mathsize 14px style C H subscript 3 C O O H end style tersebut membentuk larutan penyangga asam. 

pH = 6, berarti: begin mathsize 14px style open square brackets H to the power of plus sign close square brackets equals 10 to the power of negative sign 6 end exponent end style 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell K subscript a cross times fraction numerator open square brackets C H subscript 3 C O O H close square brackets over denominator open square brackets C H subscript 3 C O O Na close square brackets end fraction end cell row cell 10 to the power of negative sign 6 end exponent end cell equals cell 10 to the power of negative sign 5 end exponent cross times fraction numerator left parenthesis begin display style bevelled fraction numerator 10 minus sign 0 comma 2 x space mmol over denominator 100 space mL end fraction end style right parenthesis over denominator left parenthesis begin display style bevelled fraction numerator 0 comma 1 x space mmol over denominator 100 space mL end fraction end style right parenthesis end fraction end cell row cell 0 comma 1 end cell equals cell fraction numerator 10 minus sign 0 comma 2 x over denominator 0 comma 1 x end fraction end cell row cell 0 comma 01 x end cell equals cell 10 minus sign 0 comma 2 x end cell row cell 0 comma 01 x plus 0 comma 2 x end cell equals 10 row cell 0 comma 21 x end cell equals 10 row x equals cell 47 comma 6 space mL end cell end table end style 

begin mathsize 14px style V space Na O H double bond x space mL equals 47 comma 6 space mL V space C H subscript 3 C O O H equals left parenthesis 100 minus sign x right parenthesis space mL equals 52 comma 4 space mL end style 


Jadi, volume larutan begin mathsize 14px style bottom enclose Na O H end enclose end style 0,1 molar dan begin mathsize 14px style bottom enclose C H subscript bold 3 C O O H end enclose end style 0,1 molar yang diperlukan berturut-turut adalah 47,6 mL dan 52,4 mL.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 26 Juli 2021

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved