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Berapa pH maksimum penambahan larutan NaOH agar kadar Pb maksimum 3 ppm, jika Ksp Pb(OH)2= (Ar Pb=120)?

Pertanyaan

Berapa pH maksimum penambahan larutan NaOH agar kadar Pb maksimum 3 ppm, jika Ksp Pb(OH)2=1 cross times 10 to the power of negative sign 12 end exponent (Ar Pb=120)?space

Pembahasan Soal:

Soal ini menggabungkan ion senama dengan pH dan Ksp. Penggabungan ini dapat dilihat dari larutan NaOH dengan data Ksp yang diketahui, yaitu Pb(OH)2. Pada kedua larutan memiliki ion senama yaitu OH-.

Untuk menentukan pH maksimum pada larutan NaOH, dengan menentukan [Pb2+] dari Kadar Pb yang diketahui 3 ppm, artinya terdapat 3 miligram Pb dalam satu liter larutan.

open square brackets Pb to the power of 2 plus sign close square brackets equals fraction numerator 3 cross times 10 to the power of negative sign 3 end exponent over denominator 120 end fraction cross times 1000 over 1000 open square brackets Pb to the power of 2 plus sign close square brackets equals 2 comma 5 cross times 10 to the power of negative sign 5 end exponent space M

Pb open parentheses O H close parentheses subscript 2 subscript open parentheses italic s close parentheses end subscript rightwards harpoon over leftwards harpoon Pb to the power of 2 plus sign subscript open parentheses italic a italic q close parentheses end subscript plus 2 O H to the power of minus sign subscript open parentheses italic a italic q close parentheses end subscript space space space space s space space space space space space space space space space space 2 comma 5 cross times 10 to the power of negative sign 5 end exponent M space space space space space 2 s K subscript sp equals open square brackets Pb to the power of 2 plus sign close square brackets space open square brackets O H to the power of minus sign close square brackets squared 1 cross times 10 to the power of negative sign 12 end exponent equals open parentheses 25 cross times 10 to the power of negative sign 6 end exponent close parentheses space open square brackets O H to the power of minus sign close square brackets squared open square brackets O H to the power of minus sign close square brackets equals 2 cross times 10 to the power of negative sign 4 end exponent space M

Na O H yields Na to the power of plus sign and O H to the power of minus sign space space space space space space space space space space space space space space space space space space space space space space 2 cross times 10 to the power of negative sign 4 end exponent space M pOH equals minus sign log space open square brackets O H to the power of minus sign close square brackets space space space space space space space equals minus sign log space open parentheses space 2 cross times 10 to the power of negative sign 4 end exponent close parentheses pOH equals 4 minus sign log space 2 pH and pOH equals 14 pH equals 14 minus sign open parentheses 4 minus sign log space 2 close parentheses pH equals 10 plus log space 2

Maka, pH maksimum penambahan larutan NaOH adalah 10+ log 2.space

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 06 Mei 2021

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