Roboguru

Berapa gram  (Mr=255) yang harus dicampurkan denga...

Berapa gram begin mathsize 14px style open parentheses C H subscript 3 C O O close parentheses subscript 2 Ba end style (Mr=255) yang harus dicampurkan dengan 100 mL larutan begin mathsize 14px style C H subscript 3 C O O H end style 0,1 M agar diperoleh larutan dengan pH = 5 - log 4, jika diketahui begin mathsize 14px style K subscript a end style asam asetat begin mathsize 14px style equals 10 to the power of negative sign 5 end exponent end style 

  1. ....

  2. ....undefined

Jawaban:

pH= 5-log 4

table attributes columnalign right center left columnspacing 0px end attributes row cell open square brackets H to the power of plus sign close square brackets end cell equals cell 4 space cross times space 10 to the power of negative sign 5 end exponent end cell row cell open square brackets H to the power of plus sign close square brackets end cell equals cell Ka space cross times space fraction numerator mol space asam space lemah over denominator valensi space C H subscript 3 C O O to the power of minus sign cross times mol space garam end fraction end cell row cell 4 space cross times space 10 to the power of negative sign 5 end exponent end cell equals cell 10 to the power of negative sign 5 end exponent space cross times space fraction numerator 10 space mmol over denominator 2 cross times space mol space garam end fraction end cell row cell mol space garam end cell equals cell fraction numerator 10 space mmol over denominator 8 end fraction end cell row g equals cell 1 comma 25 space mmol end cell row g equals cell 1 comma 25 space cross times space 10 to the power of negative sign 3 space end exponent mol end cell row cell Massa space open parentheses C H subscript 3 C O O close parentheses subscript 2 Ba end cell equals cell mol space cross times space M subscript r end cell row cell Massa space open parentheses C H subscript 3 C O O close parentheses subscript 2 Ba end cell equals cell 1 comma 25 space cross times space 10 to the power of negative sign 3 end exponent space cross times space 255 end cell row cell Massa space open parentheses C H subscript 3 C O O close parentheses subscript 2 Ba end cell equals cell 0 comma 3185 space gram end cell end table  

Jadi, massa begin mathsize 14px style open parentheses C H subscript 3 C O O close parentheses subscript 2 Ba end style adalah 0,3185 gram 

0

Ruangguru

RUANGGURU HQ

Jl. Dr. Saharjo No.161, Manggarai Selatan, Tebet, Kota Jakarta Selatan, Daerah Khusus Ibukota Jakarta 12860

Coba GRATIS Aplikasi Ruangguru

Produk Ruangguru

Produk Lainnya

Hubungi Kami

Ikuti Kami

©2021 Ruangguru. All Rights Reserved