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Berapa gram massa amonium nitrat yang terlarut dal...

Berapa gram massa amonium nitrat yang terlarut dalam 250 mL amonium nitrat yang pH nya 5,5 ? Diketahui begin mathsize 14px style K subscript b space N H subscript 4 O H equals 10 to the power of negative sign 5 end exponent space comma space Mr space N H subscript 4 N O subscript 3 equals 80 end style 

Jawaban:

Hitung konsentrasi [H+] berdasarkan pH,

begin mathsize 14px style space space space space pH equals minus sign log open square brackets H to the power of plus sign close square brackets space space space 5 comma 5 equals minus sign log open square brackets H to the power of plus sign close square brackets open square brackets H to the power of plus sign close square brackets equals 10 to the power of negative sign 5 comma 5 end exponent space space space space space end style  

Hitung konsentrasi garam berdasarkan konsentrasi [H+]

begin mathsize 14px style space space open square brackets H to the power of plus sign close square brackets equals square root of K subscript w over Kb middle dot open square brackets garam close square brackets end root 10 to the power of negative sign 5 comma 5 end exponent equals square root of 10 to the power of negative sign 14 end exponent over 10 to the power of negative sign 5 end exponent middle dot open square brackets N H subscript 4 N O subscript 3 close square brackets end root 10 to the power of negative sign 11 end exponent equals 10 to the power of negative sign 9 end exponent middle dot open square brackets N H subscript 4 N O subscript 3 close square brackets open square brackets N H subscript 4 N O subscript 3 close square brackets equals 10 to the power of negative sign 2 end exponent space M end style 

Hitung massa garam NH4NO3 berdasarkan konsentrasi yang diperoleh,

begin mathsize 14px style M equals mol over volume space space space space equals fraction numerator massa over Mr over denominator Volume end fraction  massa space equals M middle dot V middle dot Mr space space space space space space space space space space space space space equals 0 comma 01 middle dot 0 comma 25 middle dot 80 space space space space space space space space space space space space space equals 0 comma 2 space gram end style 

Jadi, massa amonium nitrat yang diperlukan adalah 0,2 gram

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