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Bentuk sederhana dari (23)4×(23)−5adalah ....

Pertanyaan

Bentuk sederhana dari open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent spaceadalah ....

  1. 16 space

  2. 8 space

  3. 6 space

  4. 1 over 6 space

  5. 1 over 8 space

Pembahasan Video:

Pembahasan:

Bentuk sederhana dari open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent spaceadalah ....

Berdasarkan sifat eksponen yaitu open parentheses text a end text to the power of m close parentheses to the power of n equals text a end text to the power of m cross times n end exponent comma maka diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of 3 cross times 4 end exponent cross times 2 to the power of 3 cross times open parentheses negative 5 close parentheses end exponent end cell row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of 12 cross times 2 to the power of negative 15 end exponent end cell end table


Berdasarkan sifat eksponen yaitu text a end text to the power of text m end text end exponent cross times text a end text to the power of text n end text end exponent equals text a end text to the power of text m end text plus text n end text end exponent comma maka diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of 3 cross times 4 end exponent cross times 2 to the power of 3 cross times open parentheses negative 5 close parentheses end exponent end cell row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of 12 cross times 2 to the power of negative 15 end exponent end cell row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of 12 plus left parenthesis negative 15 right parenthesis end exponent end cell row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of negative 3 end exponent end cell end table


Berdasarkan sifat eksponen yaitu text a end text to the power of text -n end text end exponent equals 1 over text a end text to the power of text n end text end exponent comma maka diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of 3 cross times 4 end exponent cross times 2 to the power of 3 cross times open parentheses negative 5 close parentheses end exponent end cell row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of 12 cross times 2 to the power of negative 15 end exponent end cell row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of 12 plus left parenthesis negative 15 right parenthesis end exponent end cell row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 2 to the power of negative 3 end exponent end cell row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 1 over 2 cubed end cell row cell open parentheses 2 cubed close parentheses to the power of 4 cross times open parentheses 2 cubed close parentheses to the power of negative 5 end exponent space end cell equals cell 1 over 8 end cell end table


Oleh karena itu, jawaban yang benar adalah E.

Jawaban terverifikasi

Dijawab oleh:

N. Puspita

Terakhir diupdate 07 Oktober 2021

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