Roboguru

Bentuk  dapat disederhanakan menjadi...

Pertanyaan

Bentuk begin mathsize 14px style open parentheses fraction numerator x to the power of begin display style 2 over 3 end style end exponent y to the power of negative begin display style 4 over 3 end style end exponent over denominator y to the power of begin display style 2 over 3 end style end exponent x squared end fraction close parentheses to the power of negative 3 over 4 end exponent end style dapat disederhanakan menjadi...

  1. begin mathsize 14px style square root of x y squared end root end style 

  2. begin mathsize 14px style x square root of y end style  

  3. begin mathsize 14px style square root of x squared y end root end style 

  4. begin mathsize 14px style x y square root of y end style  

  5. begin mathsize 14px style x y square root of x end style   

Pembahasan Soal:

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator x to the power of begin display style 2 over 3 end style end exponent y to the power of negative begin display style 4 over 3 end style end exponent over denominator y to the power of begin display style 2 over 3 end style end exponent x squared end fraction close parentheses to the power of negative 3 over 4 end exponent end cell equals cell fraction numerator x to the power of begin display style open parentheses 2 over 3 cross times negative 3 over 4 close parentheses end style end exponent y to the power of open parentheses negative begin display style 4 over 3 cross times negative 3 over 4 end style close parentheses end exponent over denominator y to the power of begin display style open parentheses 2 over 3 cross times negative 3 over 4 close parentheses end style end exponent x to the power of open parentheses 2 cross times negative begin display style 3 over 4 end style close parentheses end exponent end fraction end cell row blank equals cell fraction numerator x to the power of negative begin display style 1 half end style end exponent y over denominator y to the power of negative begin display style 1 half end style end exponent x to the power of negative begin display style 3 over 2 end style end exponent end fraction end cell row blank equals cell x to the power of open parentheses negative 1 half minus open parentheses negative 3 over 2 close parentheses close parentheses end exponent y to the power of open parentheses 1 minus open parentheses negative 1 half close parentheses close parentheses end exponent end cell row blank equals cell x y to the power of 3 over 2 end exponent end cell row blank equals cell x y square root of y end cell end table end style 

Jadi, jawaban yang tepat adalah D.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 06 Februari 2021

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