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Benda hitam dengan daya radiasi , meradiasi gelomb...

Benda hitam dengan daya radiasi begin mathsize 14px style 150 space watt end style, meradiasi gelombang inframerah sebesar begin mathsize 14px style 22 percent sign end style dari total radiasi cahaya yang dilepaskan. Jika panjang gelombang cahaya merah begin mathsize 14px style 6000 space Angstrom end style dan begin mathsize 14px style h equals 6 comma 6 cross times 10 to the power of negative 34 end exponent space Js end stylebegin mathsize 14px style c equals 3 cross times 10 to the power of 8 space bevelled straight m over straight s end style, maka jumlah foton yang dipancarkan tiap sekon adalah...

  1. begin mathsize 14px style 1 comma 8 cross times 10 to the power of 20 space foton end style 

  2. size 14px 1 size 14px comma size 14px 0 size 14px cross times size 14px 10 to the power of size 14px 20 size 14px space size 14px foton 

  3. size 14px 1 size 14px comma size 14px 2 size 14px cross times size 14px 10 to the power of size 14px 20 size 14px space size 14px foton 

  4. size 14px 2 size 14px comma size 14px 0 size 14px cross times size 14px 10 to the power of size 14px 21 size 14px space size 14px foton 

  5. size 14px 2 size 14px comma size 14px 0 size 14px cross times size 14px 10 to the power of size 14px 19 size 14px space size 14px foton 

Jawaban:

Energi tiap foton cahaya merah adalah:

begin mathsize 14px style E equals h f E equals h c over lambda E equals 6 comma 6 cross times 10 to the power of negative 34 end exponent fraction numerator 3 cross times 10 to the power of 8 over denominator 6 cross times 10 to the power of negative 7 end exponent end fraction E equals 3 comma 3 cross times 10 to the power of negative 19 end exponent space straight J end style 

Energi total foton cahaya merah tiap detik:

begin mathsize 14px style E subscript t o t a l end subscript equals 150 times 22 percent sign E subscript t o t a l end subscript equals 33 space straight J end style  

Jumlah foton tiap detik:

begin mathsize 14px style n equals E subscript t o t a l end subscript over E n equals fraction numerator 33 over denominator 3 comma 3 cross times 10 to the power of negative 19 end exponent end fraction n equals 1 comma 0 cross times 10 to the power of 20 space foton end style 

Jadi, jawaban yang tepat adalah B.

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