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Air mengalir dalam sebuah venturimeter dengan mano...

Air mengalir dalam sebuah venturimeter dengan manometer seperti pada gambar berikut!

Jika luas penampang besar (titik 1) 100 undefined dan luas penampang kecil (titik 2) 60 undefined dan perbedaan tinggi raksa pada manometer 3 cm, maka kecepatan air yang masuk pada penampang 1 adalah ... (begin mathsize 14px style rho subscript blank subscript r a k s a end subscript end subscript equals 13.600 space kg divided by straight m cubed end stylebegin mathsize 14px style g equals 9 comma 8 space straight m divided by straight s squared end style, dan begin mathsize 14px style rho subscript a i r end subscript equals 1.000 space kg divided by straight m cubed end style

  1. 0,08 m/s

  2. 0,12 m/s

  3. 0,16 m/s

  4. 0,32 m/s

  5. 0,42 m/s

Jawaban:

Diketahui:

begin mathsize 14px style h equals 3 space cm equals 3 cross times 10 to the power of negative 2 end exponent space straight m A subscript 1 equals 100 space cm squared equals 10 to the power of negative 2 end exponent space straight m squared A subscript 2 equals 60 space cm squared equals 6 cross times 10 to the power of negative 3 end exponent space straight m squared rho subscript r a k s a end subscript equals 13.600 space kg divided by straight m cubed rho subscript a i r end subscript equals 1.000 space kg divided by straight m cubed g equals 9 comma 8 space straight m divided by straight s squared end style

Ditanya: undefined 

Jawab:

begin mathsize 14px style v subscript 1 equals square root of fraction numerator 2 g h open parentheses rho subscript r a k s a end subscript minus rho subscript a i r end subscript close parentheses over denominator rho subscript a i r end subscript open parentheses begin display style A subscript 1 squared over A subscript 2 squared end style minus 1 close parentheses end fraction end root space space space space equals square root of fraction numerator 2 cross times 9 comma 8 cross times 3 cross times 10 to the power of negative 2 end exponent open parentheses 13.600 minus 1.000 close parentheses over denominator 1.000 open parentheses begin display style open parentheses 100 close parentheses squared over open parentheses 60 close parentheses squared minus 1 end style close parentheses end fraction end root space space space space equals square root of fraction numerator 58 comma 8 cross times 10 to the power of negative 2 end exponent open parentheses 12.600 close parentheses over denominator 1.000 open parentheses begin display style open parentheses 5 over 3 close parentheses squared minus 1 end style close parentheses end fraction end root space space space space equals square root of fraction numerator 7.408 comma 8 over denominator 1.000 open parentheses begin display style 25 over 9 minus 1 end style close parentheses end fraction end root space space space space equals square root of fraction numerator 7 comma 4088 over denominator open parentheses begin display style 16 over 9 end style close parentheses end fraction end root space space space space equals 3 over 4 square root of 7 comma 4088 end root space space space space equals 3 over 4 open parentheses 2 comma 72 close parentheses space space space space equals 2 comma 04 space straight m divided by straight s end style 

Sepertinya ada kesalahan pada bagian ini sehingga tidak ada jawaban yang sesuai.

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