Roboguru

Air mengalami ionisasi menurut reaksi: , Jika pada suhu 292 K, Kw air = 1,0x10-14, maka air mumi memiliki konsentrasi H+ sama dengan konsentrasi OH- yaitu ...

Pertanyaan

Air mengalami ionisasi menurut reaksi:
begin mathsize 14px style H subscript 2 O open parentheses italic l close parentheses equilibrium H to the power of plus sign open parentheses italic a italic q close parentheses plus O H to the power of minus sign open parentheses italic a italic q close parentheses end style, Jika pada suhu 292 K, Kw air = 1,0x10-14, maka air mumi memiliki konsentrasi H+ sama dengan konsentrasi OH- yaitu ...undefined

  1. begin mathsize 14px style 1 comma 0 space cross times space 10 to the power of negative sign 7 end exponent end style 

  2. begin mathsize 14px style 1 over 18 space cross times space 10 to the power of negative sign 7 end exponent end style 

  3. begin mathsize 14px style fraction numerator 18 over denominator 100 space end fraction space cross times space 10 to the power of negative sign 7 end exponent end style 

  4. begin mathsize 14px style 1000 over 18 space cross times space 10 to the power of negative sign 7 end exponent end style 

  5. begin mathsize 14px style fraction numerator 1 comma 8 over denominator 1000 end fraction space cross times space 10 to the power of negative sign 7 end exponent end style 

Pembahasan Soal:

Tetapan kesetimbangan air Kw dinyatakan dengan:
 

begin mathsize 14px style table attributes columnalign right center left columnspacing 0px end attributes row cell K subscript w end cell equals cell fraction numerator open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets over denominator open square brackets H subscript 2 O close square brackets end fraction end cell row cell K subscript w open square brackets H subscript 2 O close square brackets end cell equals cell open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row cell K subscript w end cell equals cell open square brackets H to the power of plus sign close square brackets open square brackets O H to the power of minus sign close square brackets end cell row cell 1 comma 0 cross times 10 to the power of negative sign 14 end exponent end cell equals cell x squared end cell row x equals cell open square brackets H to the power of plus sign close square brackets equals open square brackets O H to the power of minus sign close square brackets equals 1 comma 0 cross times 10 to the power of negative sign 7 end exponent end cell end table end style 
 

Jadi, dapat disimpulkan jawaban yang tepat adalah A.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 01 April 2021

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