Roboguru

adalah ....

Pertanyaan

limit as x rightwards arrow 2 of fraction numerator x minus 2 over denominator square root of 4 x plus 1 end root minus 3 end fraction adalah ....

Pembahasan Soal:

Menentukan limit dari suatu fungsi dengan menggunakan metode mengalikan akar sekawan sebagai berikut :

table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow 2 of fraction numerator x minus 2 over denominator square root of 4 x plus 1 end root minus 3 end fraction end cell equals cell limit as x rightwards arrow 2 of fraction numerator x minus 2 over denominator square root of 4 x plus 1 end root minus 3 end fraction cross times fraction numerator square root of 4 x plus 1 end root plus 3 over denominator square root of 4 x plus 1 end root plus 3 end fraction end cell row blank equals cell limit as x rightwards arrow 2 of fraction numerator open parentheses x minus 2 close parentheses cross times square root of 4 x plus 1 end root plus 3 over denominator 4 x plus 8 end fraction end cell row blank equals cell limit as x rightwards arrow 2 of fraction numerator up diagonal strike open parentheses x minus 2 close parentheses end strike cross times open parentheses square root of 4 x plus 1 end root plus 3 close parentheses over denominator 4 left parenthesis up diagonal strike x minus 2 right parenthesis end strike end fraction end cell row blank equals cell limit as x rightwards arrow 2 of fraction numerator square root of 4 x plus 1 end root plus 3 over denominator 4 end fraction end cell row blank equals cell fraction numerator square root of 4 cross times 2 plus 1 end root plus 3 over denominator 4 end fraction end cell row blank equals cell fraction numerator square root of 9 plus 3 over denominator 4 end fraction end cell row blank equals cell fraction numerator 3 plus 3 over denominator 4 end fraction end cell row blank equals cell 6 over 4 end cell row blank equals cell 3 over 2 end cell end table

Jadi, limit as x rightwards arrow 2 of fraction numerator x minus 2 over denominator square root of 4 x plus 1 end root minus 3 end fraction adalah 3 over 2.

Pembahasan terverifikasi oleh Roboguru

Terakhir diupdate 18 Mei 2021

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