Pertanyaan

x → ∞ lim 2 x − 8 2 x + 1 − 3 = ....

$x \to \infty lim \frac{2 x + 1 - 3}{2 x - 8} = ....$

H. Hermawan

Master Teacher

Mahasiswa/Alumni Universitas Lampung

Jawaban terverifikasi

Jawaban

hasil dari adalah 0.

hasil dari $table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow infinity of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator square root of 2 x plus 1 end root minus 3 over denominator 2 x minus 8 end fraction end cell end table$ adalah 0.

Pembahasan

Limit tak hingga dapat diselesaikan dengan membagi seluruh suku dengan variabel yang memiliki derajat tertinggi. Jadi, hasil dari adalah 0.

Limit tak hingga dapat diselesaikan dengan membagi seluruh suku dengan variabel yang memiliki derajat tertinggi.

$table attributes columnalign right center left columnspacing 0px end attributes row cell limit as x rightwards arrow infinity of fraction numerator square root of 2 x plus 1 end root minus 3 over denominator 2 x minus 8 end fraction end cell equals cell limit as x rightwards arrow infinity of fraction numerator square root of begin display style fraction numerator 2 x over denominator x squared end fraction end style plus begin display style 1 over x squared end style end root minus begin display style 3 over x end style over denominator begin display style fraction numerator 2 x over denominator x end fraction end style minus begin display style 8 over x end style end fraction end cell row blank equals cell limit as x rightwards arrow infinity of fraction numerator square root of begin display style 2 over x plus 1 over x squared end style end root minus begin display style 3 over x end style over denominator begin display style 2 minus 8 over x end style end fraction end cell row blank equals cell fraction numerator square root of begin display style 2 over infinity plus 1 over infinity squared end style end root minus begin display style 3 over infinity end style over denominator begin display style 2 minus 8 over infinity end style end fraction end cell row blank equals cell fraction numerator square root of 0 minus 0 over denominator 2 minus 0 end fraction end cell row blank equals cell 0 over 2 end cell row blank equals 0 end table$

Jadi, hasil dari $table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell limit as x rightwards arrow infinity of end cell end table table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator square root of 2 x plus 1 end root minus 3 over denominator 2 x minus 8 end fraction end cell end table$ adalah 0.