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Pertanyaan

cube root of 64 cross times cube root of 343 plus 125 equals horizontal ellipsis 

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell cube root of 64 cross times cube root of 343 plus 125 end cell equals cell cube root of 16 cross times 4 end root cross times cube root of 49 cross times 7 end root plus 125 end cell row blank equals cell cube root of 4 cross times 4 cross times 4 end root cross times cube root of 7 cross times 7 cross times 7 end root plus 125 end cell row blank equals cell cube root of 4 cubed end root cross times cube root of 7 cubed end root plus 125 end cell row blank equals cell 4 cross times 7 plus 125 end cell row blank equals cell 28 plus 125 end cell row blank equals 153 end table 

Maka, hasil dari operasi bilangan tersebut adalah 153.

Pembahasan terverifikasi oleh Roboguru

Dijawab oleh:

P. Tessalonika

Mahasiswa/Alumni Universitas Negeri Medan

Terakhir diupdate 02 Mei 2021

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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Pertanyaan yang serupa

Hasil dari  adalah ….

Pembahasan Soal:

Untuk menentukan hasil dari undefined, perhatikan perhitungan berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell 11 cubed cross times 11 to the power of 5 end cell equals cell 11 cross times 11 cross times 11 cross times 11 cross times 11 cross times 11 cross times 11 cross times 11 end cell row blank equals cell 11 to the power of 8 end cell end table

Dengan demikian, hasil dari 11 cubed cross times 11 to the power of 5 adalah 11 to the power of 8.

Jadi, jawaban yang tepat adalah B.

0

Roboguru

Jika  dan , nilai dari  adalah ....

Pembahasan Soal:

Ingat!

Sifat perpangkatan antara lain:

  1. open parentheses a cross times b close parentheses to the power of m equals a to the power of m cross times b to the power of m 
  2. a to the power of m cross times a to the power of n equals a to the power of m plus n end exponent 
  3. a to the power of m space colon space a to the power of n equals a to the power of m minus n end exponent 
  4. a to the power of negative m end exponent equals 1 over a to the power of m space d e n g a n space a to the power of m not equal to 0 

Untuk begin mathsize 14px style a equals 4 end style dan begin mathsize 14px style b equals 5 end style, diperoleh

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator 4 to the power of 5 open parentheses 4 to the power of negative 2 end exponent times 5 close parentheses over denominator open parentheses 4 times 5 close parentheses squared end fraction end cell equals cell fraction numerator 4 to the power of 5 times 4 to the power of negative 2 end exponent times 5 over denominator 4 squared times 5 squared end fraction space bold left parenthesis bold sifat bold space bold 1 bold right parenthesis end cell row blank equals cell fraction numerator 4 to the power of 5 plus left parenthesis negative 2 right parenthesis end exponent times 5 over denominator 4 squared times 5 squared end fraction space bold left parenthesis bold sifat bold space bold 2 bold right parenthesis end cell row blank equals cell fraction numerator 4 cubed times 5 over denominator 4 squared times 5 squared end fraction end cell row blank equals cell 4 to the power of 3 minus 2 end exponent times 5 to the power of 1 minus 2 end exponent space bold left parenthesis bold sifat bold space bold 3 bold right parenthesis end cell row blank equals cell 4 times 5 to the power of negative 1 end exponent end cell row blank equals cell 4 times 1 fifth space bold left parenthesis bold sifat bold space bold 4 bold right parenthesis end cell row blank equals cell 4 over 5 end cell end table 

Jadi, begin mathsize 14px style fraction numerator a to the power of 5 open parentheses a to the power of negative 2 end exponent b close parentheses over denominator open parentheses a b close parentheses squared end fraction end styleequals table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell 4 over 5 end cell end table.

0

Roboguru

Sederhanakanlah persamaan berikut !

Pembahasan Soal:

table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator straight a cubed times straight b to the power of negative 2 end exponent over denominator straight a squared times straight b to the power of negative 5 end exponent times straight c to the power of negative 3 end exponent end fraction end cell equals cell straight a to the power of 3 minus 2 end exponent times straight b to the power of negative 2 plus 5 end exponent times straight c cubed end cell row blank equals cell straight a times straight b cubed times straight c cubed end cell end table


Jadi bentuk sederhana dari fraction numerator straight a cubed times straight b to the power of negative 2 end exponent over denominator straight a squared times straight b to the power of negative 5 end exponent times straight c to the power of negative 3 end exponent end fraction adalah table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell straight a times straight b cubed times straight c cubed end cell end table.

0

Roboguru

Bentuk sederhana dari  adalah ....

Pembahasan Soal:

begin mathsize 14px style 6 to the power of 4 cross times 8 squared cross times 9 cubed equals 6 to the power of 4 cross times open parentheses 2 cubed close parentheses squared cross times open parentheses 3 squared close parentheses cubed space space space space space space space space space space space space space space space space space space space equals 6 to the power of 4 cross times 2 to the power of 6 cross times 3 to the power of 6 space space space space space space space space space space space space space space space space space space space equals 6 to the power of 4 cross times left parenthesis 2 cross times 3 right parenthesis to the power of 6 space space space space space space space space space space space space space space space space space space space equals 6 to the power of 4 cross times 6 to the power of 6 space space space space space space space space space space space space space space space space space space space equals 6 to the power of 10 end style

Jadi, jawaban yang tepat A.

1

Roboguru

Hasil dari (a2b−2)(a−3b3)4 adalah ....

Pembahasan Soal:

Gunakan sifat bilangan berpangkat berikut :

(an)man×am==an×mam+n 

Maka pada soal berlaku :

(a2b2)(a3b3)4====(a2b2)×(a12b12)a212×b2+12a10×b10(ba)10  

Oleh karena itu tidak ada jawaban yang tepat.

0

Roboguru

Roboguru sudah bisa jawab 91.4% pertanyaan dengan benar

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