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Pertanyaan

D ik e t ah u i f u n g s i f d e n g an r u m u s f ( x ) = 2 x − 3 d an f − 1 a d a l ah f u n g s i in v ers d a r i f . N i l ai d a r i f − 1 ( − 1 ) a d a l ah ...

  1. -2

  2. -1

  3. 1

  4. 2

  5. 3

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D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

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Pembahasan

f left parenthesis x right parenthesis equals 2 x minus 3  M i s a l space y equals 2 x minus 3 comma space m a k a  f left parenthesis x right parenthesis equals y left right arrow x equals f to the power of negative 1 end exponent left parenthesis y right parenthesis  y equals 2 x minus 3  2 x equals y plus 3  x equals fraction numerator y plus 3 over denominator 2 end fraction  f to the power of negative 1 end exponent left parenthesis y right parenthesis equals fraction numerator y plus 3 over denominator 2 end fraction comma space m a k a colon  f to the power of negative 1 end exponent left parenthesis x right parenthesis equals fraction numerator y plus 3 over denominator 2 end fraction  J a d i rightwards arrow f to the power of negative 1 end exponent left parenthesis negative 1 right parenthesis equals fraction numerator negative 1 plus 3 over denominator 2 end fraction equals 2 over 2 equals 1

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