Pertanyaan

integral x open parentheses 3 x minus 1 close parentheses cos open parentheses 2 x cubed minus x squared plus 12 close parentheses d x equals horizontal ellipsis

  1. 1 half x squared open parentheses 3 x minus 1 close parentheses cos open parentheses 2 x cubed minus x squared plus 12 close parentheses plus C

  2. x open parentheses 3 x minus 1 close parentheses sin open parentheses 2 x cubed minus x squared plus 12 close parentheses plus C

  3. 2 sin open parentheses 2 x cubed minus x squared plus 12 close parentheses plus C

  4. 1 half sin open parentheses 2 x cubed minus x squared plus 12 close parentheses plus C

  5. 1 half cos open parentheses 2 x cubed minus x squared plus 12 close parentheses plus C

N. Ayu

Master Teacher

Mahasiswa/Alumni Universitas Negeri Padang

Jawaban terverifikasi

Pembahasan

Gunakan integral subtitusi : Jadi,

Gunakan integral subtitusi :

u equals 2 x cubed minus x squared plus 12  fraction numerator d u over denominator d x end fraction equals 6 x squared minus 2 x  d x equals fraction numerator d u over denominator 2 x open parentheses 3 x minus 1 close parentheses end fraction

Jadi,

integral x open parentheses 3 x minus 1 close parentheses cos open parentheses 2 x cubed minus x squared plus 12 close parentheses d x  equals integral x open parentheses 3 x minus 1 close parentheses cos u fraction numerator d u over denominator 2 x open parentheses 3 x minus 1 close parentheses end fraction  equals integral 1 half cos u d u  equals 1 half sin u plus C  equals 1 half sin open parentheses 2 x cubed minus x squared plus 12 close parentheses plus C

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