Pertanyaan

d ik e t ah u i f u n g s i g ( x ) = x − 1 x + 3 , x  = 1. I n v ers f u n g s i g − 1 ( x ) = ...

$d ik e t ah u i f u n g s i g (x) = \frac{x + 3}{x - 1}, x \neq = 1. I n v ers f u n g s i g^{- 1} (x) = ...$

$fraction numerator x plus 3 over denominator x minus 1 end fraction comma x not equal to 1$
$fraction numerator x plus 3 over denominator x plus 1 end fraction comma x not equal to negative 1$
$fraction numerator x plus 1 over denominator x minus 3 end fraction comma x not equal to 3$
$fraction numerator x plus 1 over denominator x plus 3 end fraction comma x not equal to negative 3$
$fraction numerator x minus 1 over denominator x minus 3 end fraction comma x not equal to 3$

N. Mustikowati

Master Teacher

Mahasiswa/Alumni Universitas Negeri Jakarta

Jawaban terverifikasi

Pembahasan

$J i k a space g left parenthesis x right parenthesis space equals space fraction numerator a x plus b over denominator c x plus d end fraction space space space m a k a space g space to the power of negative 1 end exponent left parenthesis x right parenthesis space equals space fraction numerator negative d x plus b over denominator c x minus a end fraction space space space space D a r i space f u n g s i space g left parenthesis x right parenthesis space equals fraction numerator space left parenthesis x plus 3 right parenthesis over denominator left parenthesis x minus 1 right parenthesis end fraction space space space d i p e r o l e h space n i l a i space a space equals space 1 comma space b space equals space 3 comma space c space equals space 1 space d a n space d equals space minus 1 comma space m a k a colon space g space to the power of negative 1 end exponent left parenthesis x right parenthesis equals space fraction numerator negative d x plus b over denominator c x minus a end fraction space space space space space space space space space space space space space space space space space space space space space space space space space space space space space equals space space fraction numerator x plus 3 over denominator x minus 1 end fraction$