Pertanyaan

Invers fungsi f ( x ) = x − 1 2 x + 3 , x  = 1 adalah ....

$Invers fungsi f (x) = \frac{2 x + 3}{x - 1}, x \neq = 1 adalah ....$

$f apostrophe left parenthesis x right parenthesis equals fraction numerator x plus 3 over denominator x minus 2 end fraction semicolon space x not equal to 2$
$f apostrophe left parenthesis x right parenthesis equals fraction numerator x plus 3 over denominator x plus 2 end fraction semicolon space x not equal to negative 2$
$f apostrophe left parenthesis x right parenthesis equals fraction numerator x minus 3 over denominator x minus 2 end fraction semicolon space x not equal to 2$
$f apostrophe left parenthesis x right parenthesis equals fraction numerator 2 x plus 3 over denominator x plus 2 end fraction semicolon space x not equal to negative 2$
$f apostrophe left parenthesis x right parenthesis equals fraction numerator 2 x plus 3 over denominator x minus 1 end fraction semicolon space x not equal to 1$

F. Pratama

Master Teacher

Mahasiswa/Alumni Universitas Putra Indonesia YPTK Padang

Jawaban terverifikasi

Pembahasan

$Cari space invers space dengan space formula space berikut space straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis equals fraction numerator ax plus straight b over denominator cx plus straight d end fraction space rightwards double arrow space straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis equals fraction numerator negative dx plus straight b over denominator cx minus straight a end fraction straight f left parenthesis straight x right parenthesis equals fraction numerator 2 straight x plus 3 over denominator straight x minus 1 end fraction Dengan space straight a equals 1 comma space straight b equals 2 comma space straight c equals 1 space dan space straight d equals negative 1 comma space maka straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis equals fraction numerator negative left parenthesis negative 1 right parenthesis straight x plus 3 over denominator straight x minus 2 end fraction straight f to the power of negative 1 end exponent left parenthesis straight x right parenthesis equals fraction numerator straight x plus 3 over denominator straight x minus 2 end fraction semicolon space straight x not equal to 2$