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Pertanyaan

N i l ai x → 1 lim ​ x − 1 2 x 2 − 7 x + 5 ​ = ...

  1. - 5

  2. - 3

  3. 4

  4. 5

  5. 10

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I. Sutiawan

Master Teacher

Mahasiswa/Alumni Universitas Pasundan

Jawaban terverifikasi

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Pembahasan

limit as x rightwards arrow 1 of equals fraction numerator 2 x squared minus 7 x plus 5 over denominator x minus 1 end fraction equals limit as x rightwards arrow 1 of fraction numerator horizontal strike left parenthesis x minus 1 right parenthesis end strike left parenthesis 2 x minus 5 right parenthesis over denominator horizontal strike left parenthesis x minus 1 right parenthesis end strike end fraction equals limit as x rightwards arrow 1 of left parenthesis 2 x minus 5 right parenthesis equals negative 3

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