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Pertanyaan

N i l ai d a r i ∫ 0 2 ​ ( x 2 − 2 x + 1 ) d x = ...

  1. 2 over 3

  2. 1

  3. 4 over 3

  4. 5 over 3

  5. 2

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R. RGFLSATU

Master Teacher

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Pembahasan

integral subscript a superscript b k x to the power of n d x equals open square brackets fraction numerator k over denominator n plus 1 end fraction x to the power of n plus 1 end exponent close square brackets subscript a superscript b equals open parentheses fraction numerator k over denominator n plus 1 end fraction b to the power of n plus 1 end exponent close parentheses minus open parentheses fraction numerator k over denominator n plus 1 end fraction a to the power of n plus 1 end exponent close parentheses  integral subscript 0 superscript 2 left parenthesis x squared minus 2 x plus 1 right parenthesis d x equals left square bracket 1 third x cubed minus x squared plus x right square bracket subscript 0 superscript 2  equals left parenthesis 1 third left parenthesis 2 cubed right parenthesis minus 2 squared plus 2 right parenthesis minus left parenthesis 1 third left parenthesis 0 cubed right parenthesis minus 0 squared plus 0 right parenthesis  equals left parenthesis 8 over 3 minus 2 right parenthesis minus left parenthesis 0 right parenthesis equals 2 over 3

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Nilai dari ∫ 1 3 ​ ( 6 x 2 − 2 x + 7 ) d x = ....

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