(16a2b42a5b​)−1=....

Pertanyaan

begin mathsize 14px style open parentheses fraction numerator 2 a to the power of 5 b over denominator 16 a squared b to the power of 4 end fraction close parentheses to the power of negative 1 end exponent equals.... end style 

  1. begin mathsize 14px style open parentheses fraction numerator 2 b over denominator a end fraction close parentheses cubed end style 

  2. begin mathsize 14px style open parentheses fraction numerator 2 a over denominator b end fraction close parentheses cubed end style 

  3. begin mathsize 14px style open parentheses fraction numerator a over denominator 2 b end fraction close parentheses cubed end style 

  4. begin mathsize 14px style open parentheses 2 a b close parentheses cubed end style 

D. Kamilia

Master Teacher

Mahasiswa/Alumni Universitas Negeri Malang

Jawaban terverifikasi

Pembahasan

Gunakan sifat bilangan berpangkat berikut:

table attributes columnalign right center left columnspacing 2px end attributes row cell a to the power of negative m end exponent end cell equals cell 1 over a to the power of m end cell row cell open parentheses a to the power of m close parentheses to the power of n end cell equals cell a to the power of m n end exponent end cell row cell open parentheses a divided by b close parentheses to the power of m end cell equals cell a to the power of m divided by b to the power of m end cell end table

Menggunakan sifat-sifat di atas, dapat diperoleh perhitungan sebagai berikut.

table attributes columnalign right center left columnspacing 0px end attributes row cell open parentheses fraction numerator 2 a to the power of 5 b over denominator 16 a squared b to the power of 4 end fraction close parentheses to the power of negative 1 end exponent end cell equals cell left parenthesis 2 a to the power of 5 b right parenthesis to the power of negative 1 end exponent over left parenthesis 16 a squared b to the power of 4 right parenthesis to the power of negative 1 end exponent end cell row blank equals cell fraction numerator 16 a squared b to the power of 4 over denominator 2 a to the power of 5 b end fraction end cell row blank equals cell 8 a to the power of 2 minus 5 end exponent b to the power of 4 minus 1 end exponent end cell row blank equals cell 8 a to the power of negative 3 end exponent b cubed end cell row blank equals cell fraction numerator 8 b cubed over denominator a cubed end fraction end cell row blank equals cell open parentheses fraction numerator 2 b over denominator a end fraction close parentheses cubed end cell end table

Sehingga diperoleh bahwa open parentheses fraction numerator 2 a to the power of 5 b over denominator 16 a squared b to the power of 4 end fraction close parentheses to the power of negative 1 end exponent equals open parentheses fraction numerator 2 b over denominator a end fraction close parentheses cubed.

Oleh karena itu, jawaban yang tepat adalah A.

 

 

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Tsaniaturrokhmah Izzulhaq

Pembahasan tidak menjawab soal

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