Pertanyaan

cosec 6 0 ∘ cotan 4 5 ∘ sin 6 0 ∘ + tan 4 5 ∘ + cos 3 0 ∘

$\frac{sin 6 0 ^{\circ} + tan 4 5 ^{\circ} + cos 3 0 ^{\circ}}{cosec 6 0 ^{\circ} cotan 4 5 ^{\circ}}$

E. Dwi

Master Teacher

Mahasiswa/Alumni Universitas Sriwijaya

Jawaban terverifikasi

Jawaban

hasil dari adalah .

hasil dari $fraction numerator sin space 60 degree plus tan space 45 degree plus cos space 30 degree over denominator cosec space 60 degree space cotan space 45 degree end fraction$ adalah $table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator square root of 3 plus 3 over denominator 2 end fraction end cell end table$ .

Pembahasan

Hasil dari : Jadi, hasil dari adalah .

Hasil dari $fraction numerator sin space 60 degree plus tan space 45 degree plus cos space 30 degree over denominator cosec space 60 degree space cotan space 45 degree end fraction$ :

$table attributes columnalign right center left columnspacing 0px end attributes row cell fraction numerator sin space 60 degree plus tan space 45 degree plus cos space 30 degree over denominator cosec space 60 degree space cotan space 45 degree end fraction end cell equals cell fraction numerator sin space 60 degree plus tan space 45 degree plus cos space 30 degree over denominator begin display style fraction numerator 1 over denominator sin space 60 degree end fraction end style cross times begin display style fraction numerator 1 over denominator tan space 45 degree end fraction end style space end fraction end cell row blank equals cell fraction numerator begin display style 1 half end style square root of 3 plus 1 plus begin display style 1 half end style square root of 3 over denominator begin display style fraction numerator 1 over denominator begin display style 1 half end style square root of 3 end fraction end style cross times begin display style 1 over 1 end style end fraction end cell row blank equals cell fraction numerator 1 plus square root of 3 over denominator begin display style fraction numerator 2 over denominator square root of 3 end fraction end style end fraction end cell row blank equals cell fraction numerator open parentheses 1 plus square root of 3 close parentheses square root of 3 over denominator 2 end fraction end cell row blank equals cell fraction numerator square root of 3 plus 3 over denominator 2 end fraction end cell end table$

Jadi, hasil dari $fraction numerator sin space 60 degree plus tan space 45 degree plus cos space 30 degree over denominator cosec space 60 degree space cotan space 45 degree end fraction$ adalah $table attributes columnalign right center left columnspacing 0px end attributes row blank blank cell fraction numerator square root of 3 plus 3 over denominator 2 end fraction end cell end table$ .